比较2个数组并区分Java中相同位置的相同值和不同位置的相同值

Question

我碰壁了（不是字面意思）需要帮助。我对 Java 很陌生，所以需要保持这个基础才能保持我的技能水平。

我有两个包含 3 种随机颜色的 Color[] 数组。 我正在尝试识别数组中相同位置的颜色和相同但不同位置的颜色。

这对于那些熟悉 Mastermind 评分的人来说是相同的逻辑。

示例：

answerColors[]{Color.Red, Color.Blue, Color.Blue}

userColors[]{Color.Yellow,Color.Blue,Color.Red}

结果应该显示：

same color/position = 2 (this would be the Blue at [1])

same color/ different position = 1 (this would be the Red)

注意：

因为 answerColors[1] == userColors[1]，请声明其位置正确，不要声明 userColors[1] 的位置不正确。

示例 2：

answerColors[]{Color.Yellow, Color.Green, Color.Blue}

userColors[]{Color.Yellow,Color.Blue,Color.Red}

结果应该显示：

same color/position = 1 (this would be the Yellow at [0]) same color/ different position = 1 (this would be the Blue)

//How will the poster distingush the difference between (Same Color, Correct Position) and (Same Color, **Different** Position)?

我看过很多回答此类问题的帖子，但没有一个帖子在比较两个数组时解决状态{相同颜色，不同位置}，并阻止数组的相同部分被扫描两次。 （上面的例子有解释。#1 是最有帮助的。）

这是我的代码不起作用....结果应该是：

same color/same position = 2
same color/different position = 1

感谢您的帮助！

public void createScoreArray() {  // creates the array for     determining the values for the score panel (2 = same color/same position; 6 = not same color/same position; 1 = same color/different position ignoring those already in same color/same position
    answerColors[]{Color.Red, Color.Blue, Color.Blue};
    userColor[]{Color.Yellow, Color.Blue, Color.Red};
    int j = 0;
    scoreNumCheck = new int[3];
    for (int i = 0; i < answerColors.length; i++) {  // checking same color same position
        if (answerColors[i] == userColor[j]) {
            scoreNumCheck[i] = 2;
            System.out.println(scoreNumCheck[i]);
            j++;
         System.out.println("++++++++++++Score Pegs: " + Arrays.toString(scoreNumCheck));
        } else if (answerColors[i] != userColor[j]) {
            scoreNumCheck[i] = 6;
            j++;
        }
        System.out.println("--------- " + Arrays.toString(scoreNumCheck));


    }
    System.out.println("++++++++++++Score Pegs: " + Arrays.toString(scoreNumCheck));
    for (int s = 0; s < scoreNumCheck.length; s++) {
        if (scoreNumCheck[s] != 2) {
            for (int i = 0; i < answerColors.length; i++) {
                for (int u = 0; u < userColor.length; u++) {
                    if (userColor[u] == (answerColors[i])) {
                        scoreNumCheck[6] = 1;
                    }
                }
            }

        }
        System.out.println("2.  ++++++++++++Score Pegs: " + Arrays.toString(scoreNumCheck));
    }
}

Answer 1

请尝试使用方法检查问题的措辞是否为读者所理解。 （尝试让朋友阅读。）我无法理解代码。我试图重新制作代码。

package StackOverflowAnswers;

import java.awt.Color;
import java.util.LinkedList;

public class StackOverflow53568488 {
    Color[] answerColors = {Color.RED, Color.BLUE, Color.BLUE};
    Color[] userColors = {Color.YELLOW, Color.BLUE, Color.RED}; //There is no Color.Red, there is Color.RED and Color.red.
    int [] scoreNumCheck;
    public void createScoreArray() {  
 // creates the array for determining the values for the score panel 
 //(2 = same color/same position; 
 // 6 = not same color/same position; 
 // 1 = same color/different position ignoring those already in same color/same position

        scoreNumCheck = new int[3];

        LinkedList <Integer> Results = new LinkedList<Integer>(); 
        //You should only be able to get a size of 3 in this LinkedList

        for(int i=0; i<3; i++){
            if (answerColors[i] == userColors[i]){
                Results.add(2);
            }
        }
        for(int i=0; i<3; i++){
            for(int j=0; j<3; j++){
                if(answerColors[i] == userColors[j]){ // Try drawing this stuff out...
                    Results.add(1); // add scores to Results
                }
            }
        }
        while (Results.size() < 3){
            Results.add(6); // Use the fact that you should always get a size of 3 in Results to be able to add 6 until that condition is satisfied.
        }
        //I failed to understand how you printed the answers.


        //
    }
}