【发布时间】:2011-07-13 04:02:41
【问题描述】:
我使用一个简单的“计算器”项目作为圆角矩形按钮的示例。整个项目由一个小的类文件组成。这里是:
import java.awt.BorderLayout;
import java.awt.GridLayout;
import java.awt.event.KeyEvent;
import javax.swing.BorderFactory;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JMenu;
import javax.swing.JMenuBar;
import javax.swing.JPanel;
import javax.swing.JTextField;
/**
* Swing layout management tutorial
*
* This program shows how to use the
* GridLayout manager to create a
* calculator skeleton.
*
* @author jan bodnar
* website zetcode.com
* last modified February 2009
*/
public class Calculator extends JFrame {
public Calculator() {
setTitle("Calculator");
initUI();
setSize(320, 290);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setLocationRelativeTo(null);
setVisible(true);
}
public void initUI() {
JMenuBar menubar = new JMenuBar();
JMenu file = new JMenu("File");
file.setMnemonic(KeyEvent.VK_F);
menubar.add(file);
setJMenuBar(menubar);
String[] labels = {
"Cls", "Bck", "", "Close",
"7", "8", "9", "/",
"4", "5", "6", "*",
"1", "2", "3", "-",
"0", ".", "=", "+"
};
JTextField field = new JTextField();
add(field, BorderLayout.NORTH);
JPanel buttonPanel = new JPanel(new GridLayout(5, 4, 3, 3));
buttonPanel.setBorder(BorderFactory.createEmptyBorder(8, 0, 0, 0));
for (String label: labels) {
if (label.isEmpty()) {
JLabel lbl = new JLabel();
buttonPanel.add(lbl);
} else {
JButton button = new JButton(label);
buttonPanel.add(button);
}
}
add(buttonPanel, BorderLayout.CENTER);
}
public static void main(String[] args) {
new Calculator();
}
}
运行时,它会生成带有扁平、略带 3D 外观的漂亮矩形标签按钮。我试图获得如下相同的效果:
FlowLayout flowLayoutManager = new FlowLayout(FlowLayout.RIGHT);
JPanel lowerPanel = new JPanel(flowLayoutManager);
lowerPanel.setBorder(
BorderFactory.createEtchedBorder(
EtchedBorder.RAISED));
lowerPanel.setBackground(Color.ORANGE);
lowerPanel.setPreferredSize(new Dimension(700, 100));
lowerPanel.setMaximumSize(lowerPanel.getPreferredSize());
lowerPanel.setMinimumSize(lowerPanel.getPreferredSize());
/*
* cardReaderButtonPanel holds three card reader control buttons
*/
JPanel cardReaderButtonPanel = new JPanel(new GridLayout(1, 3, 10, 0));
cardReaderButtonPanel.setBorder(BorderFactory.createEmptyBorder(8, 0, 0, 0));
cardReaderButtonPanel.setOpaque(false); // transparent background
String[] labels = {"Load", "Stop", "Start"};
for (String label : labels) {
JButton button = new JButton(label);
cardReaderButtonPanel.add(button);
}
lowerPanel.add(cardReaderButtonPanel);
...但是 my 按钮看起来像 Mac OS X Aqua 菱形!与计算器示例不同,我将按钮面板添加到一个封闭面板中,该面板本身由 BorderLayout 的中心包围 - 但我看不出这会如何影响按钮的绘制方式。
【问题讨论】:
-
这是一个经常被问到的问题,事实上,这些主题中的许多都在右侧的链接列表中链接到您的问题。您的任务将涉及一些工作,但这些链接将帮助您了解如何开始。
-
我确实看到了这些链接,但我真正的问题是,我正在研究的计算器代码是如何在看似没有做任何特别的事情的情况下生成圆角矩形按钮的?我似乎无法编辑我原来的问题,所以我将通过“回答你的问题”完整地发布计算器代码(它不长)。当我编译并运行它时,我得到了方形按钮,但我不知道为什么。
-
太棒了。我无法“回答我的问题”来发布整个代码。
标签: java swing jbutton appearance