在silverlight中制作连接两个对象的线答案

【问题标题】：make line that connects two objects in silverlight在silverlight中制作连接两个对象的线
【发布时间】：2013-06-11 15:12:30
【问题描述】：

如何连接这些实体框？

框是通过单击按钮创建的，并且可以拖动。现在我想用线什么的把它们连接起来。

【问题讨论】：

标签： c# silverlight line connect

【解决方案1】：

这是一个快速而肮脏的实现：

代表连接的类：

public partial class Connection
{
    public MyBox Box1 { get; set; }
    public MyBox Box2 { get; set; }
    public Line Line { get; set; }
}

为了创建一个新连接，我使用了一个基本形式：源名称、目标名称和一个按钮：

<StackPanel Orientation="Horizontal" Grid.Row="3">
    <TextBox Width="100" Text="{Binding From,UpdateSourceTrigger=PropertyChanged,Mode=TwoWay}" />
    <TextBlock Text=" ----> " />
    <TextBox Width="100" Text="{Binding To,UpdateSourceTrigger=PropertyChanged,Mode=TwoWay}" />
    <Button Content="Connect" Click="Button_Click_2" />
</StackPanel>

这里是处理程序：

public string From { get; set; }
public string To { get; set; }

private IList<Connection> connections = new List<Connection>();
private void Button_Click_2(object sender, RoutedEventArgs e)
{
    MyBox box1 = boxes.Single(b => b.Header == From);
    MyBox box2 = boxes.Single(b => b.Header == To);

    Connection conn = new Connection { Box1 = box1, Box2 = box2, Line = new Line { StrokeThickness = 1, Stroke = Brushes.Black } };
    connections.Add(conn);

    RefreshLinesPositions();

    panel.Children.Add(conn.Line);
}

还有 RefreshLinesPositions 代码：

private void RefreshLinesPositions()
{
    foreach (Connection conn in connections)
    {
        Point p1 = conn.Box1.TranslatePoint(new Point(0, 0), panel);
        Point p2 = conn.Box2.TranslatePoint(new Point(0, 0), panel);

        double t1 = p1.Y;
        double b1 = p1.Y + conn.Box1.ActualHeight;
        double l1 = p1.X;
        double r1 = p1.X + conn.Box1.ActualWidth;

        double t2 = p2.Y;
        double b2 = p2.Y + conn.Box2.ActualHeight;
        double l2 = p2.X;
        double r2 = p2.X + conn.Box2.ActualWidth;

        if (r1 < l2)
        {
            conn.Line.X1 = r1;
            conn.Line.Y1 = t1 + (b1 - t1) / 2;
            conn.Line.X2 = l2;
            conn.Line.Y2 = t2 + (b2 - t2) / 2;

            conn.Line.Visibility = Visibility.Visible;
        }
        else if (r2 < l1)
        {
            conn.Line.X1 = r2;
            conn.Line.Y1 = t2 + (b2 - t2) / 2;
            conn.Line.X2 = l1;
            conn.Line.Y2 = t1 + (b1 - t1) / 2;

            conn.Line.Visibility = Visibility.Visible;
        }
        else if (b1 < t2)
        {
            conn.Line.X1 = l1 + (r1 - l1) / 2;
            conn.Line.Y1 = b1;
            conn.Line.X2 = l2 + (r2 - l2) / 2;
            conn.Line.Y2 = t2;

            conn.Line.Visibility = Visibility.Visible;
        }
        else if (b2 < t1)
        {
            conn.Line.X1 = l1 + (r1 - l1) / 2;
            conn.Line.Y1 = t1;
            conn.Line.X2 = l2 + (r2 - l2) / 2;
            conn.Line.Y2 = b2;

            conn.Line.Visibility = Visibility.Visible;
        }
        else
        {
            conn.Line.Visibility = System.Windows.Visibility.Collapsed;
        }
    }

每当一个盒子被移动时，你都会调用 RefreshLinesPositions：

private void Box_MouseMove(object sender, MouseEventArgs e)
{
    if (draggedBox != null)
    {
        ...

        RefreshLinesPositions();
    }
}

编辑：对于节点

新的RefreshLinesPosition版本：

private void RefreshLinesPositions()
{
    foreach (Connection conn in connections)
    {
        Point p1 = conn.Box1.TranslatePoint(new Point(0, 0), panel);
        Point p2 = conn.Box2.TranslatePoint(new Point(0, 0), panel);

        double t1 = p1.Y;
        double b1 = p1.Y + conn.Box1.ActualHeight;
        double l1 = p1.X;
        double r1 = p1.X + conn.Box1.ActualWidth;

        double t2 = p2.Y;
        double b2 = p2.Y + conn.Box2.ActualHeight;
        double l2 = p2.X;
        double r2 = p2.X + conn.Box2.ActualWidth;

        if (r1 < l2)
        {
            conn.Line.X1 = r1;
            conn.Line.Y1 = t1 + (b1 - t1) / 2;
            conn.Line.X2 = l2;
            conn.Line.Y2 = t2 + (b2 - t2) / 2;

            conn.Line.Visibility = Visibility.Visible;

            conn.Node1.Text.RenderTransform = new TranslateTransform(r1, t1 + (b1 - t1) / 2);
            conn.Node2.Text.RenderTransform = new TranslateTransform(l2 - conn.Node2.Text.ActualWidth, t2 + (b2 - t2) / 2);
        }
        else if (r2 < l1)
        {
            conn.Line.X1 = l1;
            conn.Line.Y1 = t1 + (b1 - t1) / 2;
            conn.Line.X2 = r2;
            conn.Line.Y2 = t2 + (b2 - t2) / 2;

            conn.Line.Visibility = Visibility.Visible;

            conn.Node1.Text.RenderTransform = new TranslateTransform(l1 - conn.Node1.Text.ActualWidth, t1 + (b1 - t1) / 2);
            conn.Node2.Text.RenderTransform = new TranslateTransform(r2, t2 + (b2 - t2) / 2);
        }
        else if (b1 < t2)
        {
            conn.Line.X1 = l1 + (r1 - l1) / 2;
            conn.Line.Y1 = b1;
            conn.Line.X2 = l2 + (r2 - l2) / 2;
            conn.Line.Y2 = t2;

            conn.Line.Visibility = Visibility.Visible;

            conn.Node1.Text.RenderTransform = new TranslateTransform(l1 + (r1 - l1) / 2, b1);
            conn.Node2.Text.RenderTransform = new TranslateTransform(l2 + (r2 - l2) / 2, t2 - conn.Node2.Text.ActualHeight);
        }
        else if (b2 < t1)
        {
            conn.Line.X1 = l1 + (r1 - l1) / 2;
            conn.Line.Y1 = t1;
            conn.Line.X2 = l2 + (r2 - l2) / 2;
            conn.Line.Y2 = b2;

            conn.Line.Visibility = Visibility.Visible;

            conn.Node1.Text.RenderTransform = new TranslateTransform(l1 + (r1 - l1) / 2, t1 - conn.Node1.Text.ActualHeight);
            conn.Node2.Text.RenderTransform = new TranslateTransform(l2 + (r2 - l2) / 2, b2);
        }
        else
        {
            conn.Line.Visibility = System.Windows.Visibility.Collapsed;
        }
    }
}

新的事件处理程序：

private void Button_Click_2(object sender, RoutedEventArgs e)
{
    MyBox box1 = boxes.Single(b => b.Header == From);
    MyBox box2 = boxes.Single(b => b.Header == To);

    Connection conn = new Connection
    {
        Box1 = box1,
        Box2 = box2,
        Line = new Line { StrokeThickness = 1, Stroke = Brushes.Black },
        Node1 = new Node { Text = new TextBox() },
        Node2 = new Node { Text = new TextBox() }
    };
    connections.Add(conn);

    panel.Children.Add(conn.Line);

    panel.Children.Add(conn.Node1.Text);
    panel.Children.Add(conn.Node2.Text);

    RefreshLinesPositions();
}

我用它来表示节点：

public partial class Node
{
    public string Title { get; set; }
    public TextBox Text { get; set; }
}

【讨论】：

我在“From”和“To”上遇到错误，它说它不存在
我点击连接，但没有任何反应，可能是我做错了什么
尝试调试，尤其是当您达到“conn.Line.Visibility = Visibility.Visible;”之一时
当我点击连接时，它崩溃并出现此错误：“用户代码未处理 InvalidOperationException - 序列不包含匹配元素”
@LuisAmaro: 再次SL :( 试试new TranslateTransform{ X = r1, Y = t1 + (b1 - t1) / 2) }

【解决方案2】：

你必须得到每个盒子的位置;
在方框之间画一个Path；
重绘框拖放...

带有两个 Rectangle 的简单示例：

XAML：

<Canvas x:Name="Root">
    <Rectangle
        x:Name="rect1"
        Fill="Aqua"
        Width="20"
        Height="20"
        Canvas.Left="24"
        Canvas.Top="44" />
    <Rectangle
        x:Name="rect2"
        Fill="Red"
        Width="20"
        Height="20"
        Canvas.Left="119"
        Canvas.Top="73" />
</Canvas>

C#：

ConnectBoxes(Root, rect1, rect2);
....

public void ConnectBoxes(Canvas container, Rectangle boxeSrc, Rectangle boxeDest)
{
    var transform1 = boxeSrc.TransformToVisual(container);
    var transform2 = boxeDest.TransformToVisual(container);

    var lineGeometry = new LineGeometry()
    {
        StartPoint = transform1.Transform(
            new Point(boxeSrc.ActualWidth / 2, boxeSrc.ActualHeight / 2.0)
        ),
        EndPoint = transform2.Transform(
            new Point(boxeDest.ActualWidth / 2.0, boxeDest.ActualHeight / 2.0)
        )
    };
    container.Children.Add(new Path()
    {
        Data = lineGeometry,
        Fill = new SolidColorBrush(Colors.Brown),
        Stroke = new SolidColorBrush(Colors.Brown),

    });
}

【讨论】：

这个例子很好，但是没有预制对象我怎么能做到呢？我猜想画线的更好方法是单击一个按钮，该按钮允许从一个对象到另一个对象画一条线......链接上的这个例子是完美的，但它在 wpf 上，我不能把它放在我的项目：/denisvuyka.wordpress.com/2007/10/13/…
你知道如何使路径在拖动时随矩形调整吗？