嗯。我同意@tereško 你应该使用 div。但即便如此,你也会面临同样的问题。你可以在另一组 div 旁边放一个 sortable,但 sortable 可能对你不起作用,尤其是当答案行需要与问题行的高度匹配时。
这是拖放答案所需的代码。
HTML:
<table border="1" id="qatable">
<tr>
<td>QuestionSide</td>
<td>Answer Side</td>
</tr>
<tr>
<td>Question 1 </td>
<td><div class="answer answer1"> Ans1 </div> </td>
</tr>
<tr>
<td>question 2 </td>
<td><div class="answer answer2"> Ans2 </div> </td>
</tr>
<tr>
<td> question 3</td>
<td><div class="answer answer3"> Ans3 </div> </td>
</tr>
<tr>
<td> question 4</td>
<td><div class="answer answer4"> Ans4 </div> </td>
</tr>
<tr>
<td> question 5 </td>
<td><div class="answer answer5"> Ans5 </div> </td>
</tr>
</table>
<br /><br />
<button onclick="alert($('.answer').index($('.answer1'))+1);">Get position of answer 1</button><br />
<button onclick="alert($('.answer').index($('.answer2'))+1);">Get position of answer 2</button><br />
<button onclick="alert($('.answer').index($('.answer3'))+1);">Get position of answer 3</button><br />
<button onclick="alert($('.answer').index($('.answer4'))+1);">Get position of answer 4</button><br />
<button onclick="alert($('.answer').index($('.answer5'))+1);">Get position of answer 5</button><br />
<br /><br>
<button onclick="alert($('.answer').eq(0).html());">Get answer of question 1</button><br />
<button onclick="alert($('.answer').eq(1).html());">Get answer of question 2</button><br />
<button onclick="alert($('.answer').eq(2).html());">Get answer of question 3</button><br />
<button onclick="alert($('.answer').eq(3).html());">Get answer of question 4</button><br />
<button onclick="alert($('.answer').eq(4).html());">Get answer of question 5</button><br />
这里是 jQuery 代码。确保您已包含 jquery 和 jquery ui 脚本文件。
$(document).ready(function(e) {
$('.answer').draggable({
axis: 'y',
opacity: 0.5,
containment: $('#qatable'),
revert: true,
revertDuration: 0,
distance: 10,
cursor: 'pointer'
}).droppable({
accept: '.answer',
tolerance: 'pointer',
drop: function(event, ui) {
ui.droppable = $(this);
var answers = $('#qatable').find('.answer');
toindex = answers.index(ui.droppable);
fromindex = answers.index(ui.draggable);
var placeholder = $('<div id="placeholder"> </div>').insertBefore(ui.droppable); // Placeholder
if (toindex < fromindex) { // Moving an answer up
for (var i=toindex;i<fromindex;i++) {
answers.eq(i).insertBefore(answers.eq(i+1)); // Shift everything down
}
ui.draggable.insertBefore(placeholder); // Move the draggable answer to where the other one was
placeholder.remove();
} else { // Moving the answer down
for (var i=toindex;i>fromindex;i--) {
answers.eq(i).insertBefore(answers.eq(i-1)); // Shift everything up
}
ui.draggable.insertBefore(placeholder); // Move the draggable answer to where the other one was
placeholder.remove();
}
}
});
});
无论您实际使用的是 div 还是表格单元格,都无关紧要。该代码仍然适用于 div 或表格单元格。之后您需要做的就是设置表格单元格的样式。
要获得答案的位置,只需使用 index 方法即可。
var pos = $('.answer').index($('.answer1'))+1;
要获得问题的答案,只需使用 eq 方法。只要知道它是基于 0 的,所以问题 1 的答案是 eq(0),问题 2 的答案是 eq(1),等等...
var answer = $('.answer').eq(0).html();