Java中完美的URL验证正则表达式

Question

我找到了该页面：https://mathiasbynens.be/demo/url-regex，其中很好地列出了用于 URL 验证的不同正则表达式及其可能性。 Diego Perini 的正则表达式是最强大的，我想在 Java 中使用它。但是，如果我这样使用它就行不通了：

public class URLValidation {
    // "\" replaced by "\\"
    private static Pattern REGEX = Pattern.compile("_^(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!10(?:\\.\\d{1,3}){3})(?!127(?:\\.\\d{1,3}){3})(?!169\\.254(?:\\.\\d{1,3}){2})(?!192\\.168(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\x{00a1}-\\x{ffff}0-9]+-?)*[a-z\\x{00a1}-\\x{ffff}0-9]+)(?:\\.(?:[a-z\\x{00a1}-\\x{ffff}0-9]+-?)*[a-z\\x{00a1}-\\x{ffff}0-9]+)*(?:\\.(?:[a-z\\x{00a1}-\\x{ffff}]{2,})))(?::\\d{2,5})?(?:/[^\\s]*)?$_iuS");

    private static String[] URLs = new String[] { "http://foo.com/blah_blah", "http://foo.com/blah_blah/", "http://foo.com/blah_blah_(wikipedia)", "http://foo.bar?q=Spaces should be encoded" };

    public static void main(String[] args) throws Exception {
        for (String url : URLs) {
            Matcher matcher = REGEX.matcher(url);
            if (matcher.find()) {
                System.out.println(matcher.group());
            }}}}

此代码不输出任何内容，但它应该输出数组中的前三个 URL。如何正确编译正则表达式以使代码正常工作？

upd：感谢您的建议。我在实际应用程序中测试了您的正则表达式。我在那里做的是遍历日志文件并在每一行中查找 URL。日志文件的时间戳和用户名分别包含在 [] 和 中，有时可能包含负责格式化（颜色、粗体等）的特殊不可见字符，例如 \u0003。正则表达式似乎对那种类型的字符串有问题：http://ideone.com/WEcgBY

upd2：如果正则表达式包含多个 URL，那么如何查找一行中的所有 URL？例如像这样使用它：

String[] urlsFromLine = REGEX.split(line);
for (String url : urlsFromLine) {
    System.out.println(url);
}

Answer 1

使用这个版本：

"(?i)^(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!(?:10|127)(?:\\.\\d{1,3}){3})(?!(?:169\\.254|192\\.168)(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[a-z\\u00a1-\\uffff]{2,}))\\.?)(?::\\d{2,5})?(?:[/?#]\\S*)?$"

您不必将斜杠加倍，在模式末尾添加正则表达式分隔符、修饰符，并将 \u 转换为 \x 表示法。

见IDEONE demo:

String[] URLs = new String[] { "http://foo.com/blah_blah", "http://foo.com/blah_blah/", "http://foo.com/blah_blah_(wikipedia)", "http://foo.bar?q=Spaces should be encoded" };
Pattern REGEX = Pattern.compile("(?i)^(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!(?:10|127)(?:\\.\\d{1,3}){3})(?!(?:169\\.254|192\\.168)(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[a-z\\u00a1-\\uffff]{2,}))\\.?)(?::\\d{2,5})?(?:[/?#]\\S*)?$");
for (String url : URLs) {
    Matcher matcher = REGEX.matcher(url);
    if (matcher.find()) {
       System.out.println(matcher.group());
    }
}

输出：

http://foo.com/blah_blah
http://foo.com/blah_blah/
http://foo.com/blah_blah_(wikipedia)

更新

要匹配较大文本中的 URL，您需要将 ^ 和 $ 替换为 \\b：

Pattern REGEX = Pattern.compile("(?i)\\b(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!(?:10|127)(?:\\.\\d{1,3}){3})(?!(?:169\\.254|192\\.168)(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[a-z\\u00a1-\\uffff]{2,}))\\.?)(?::\\d{2,5})?(?:[/?#]\\S*)?\\b");

见another demo