【问题标题】:How to return exception data in json format from App_Error in global.asax?如何从 global.asax 中的 App_Error 返回 json 格式的异常数据?
【发布时间】:2012-10-29 11:55:29
【问题描述】:
我正在将 Asp.net MVC 项目作为单页应用程序进行错误处理。
我想将 json 数据从 global.asax 中的 Application_Error 方法返回到 UI 并通过 jQuery 显示或调用控制器并返回部分视图。
我不想刷新页面或将其重定向到错误页面。
【问题讨论】:
标签:
json
asp.net-mvc
global-asax
【解决方案1】:
这是要走的路
protected void Application_Error(object sender, EventArgs e)
{
Exception exception = Server.GetLastError();
// if the error is NOT http error, then stop handling it.
if (!(exception is HttpException httpException))
return;
if (new HttpRequestWrapper(Request).IsAjaxRequest())
{
Response.Clear();
Response.TrySkipIisCustomErrors = true;
Server.ClearError();
Response.ContentType = "application/json";
Response.StatusCode = 400;
JsonResult json = new JsonResult
{
Data = exception.Message
};
json.ExecuteResult(new ControllerContext(Request.RequestContext, new BaseController()));
}
}
【解决方案2】:
//Write This code into your global.asax file
protected void Application_Error(Object sender, EventArgs e)
{
var ex = Server.GetLastError();
//We check if we have an AJAX request and return JSON in this case
if (IsAjaxRequest())
{
Response.Write(JsonConvert.SerializeObject(new
{
error = true,
message = "Exception: " + ex.Message
})
);
}
}
private bool IsAjaxRequest()
{
//The easy way
bool isAjaxRequest = (Request["X-Requested-With"] == "XMLHttpRequest")
|| ((Request.Headers != null)
&& (Request.Headers["X-Requested-With"] == "XMLHttpRequest"));
//If we are not sure that we have an AJAX request or that we have to return JSON
//we fall back to Reflection
if (!isAjaxRequest)
{
try
{
//The controller and action
string controllerName = Request.RequestContext.
RouteData.Values["controller"].ToString();
string actionName = Request.RequestContext.
RouteData.Values["action"].ToString();
//We create a controller instance
DefaultControllerFactory controllerFactory = new DefaultControllerFactory();
Controller controller = controllerFactory.CreateController(
Request.RequestContext, controllerName) as Controller;
//We get the controller actions
ReflectedControllerDescriptor controllerDescriptor =
new ReflectedControllerDescriptor(controller.GetType());
ActionDescriptor[] controllerActions =
controllerDescriptor.GetCanonicalActions();
//We search for our action
foreach (ReflectedActionDescriptor actionDescriptor in controllerActions)
{
if (actionDescriptor.ActionName.ToUpper().Equals(actionName.ToUpper()))
{
//If the action returns JsonResult then we have an AJAX request
if (actionDescriptor.MethodInfo.ReturnType
.Equals(typeof(JsonResult)))
return true;
}
}
}
catch
{
}
}
return isAjaxRequest;
}
//Write this code in your ajax function in html file
<script type="text/javascript">
$.ajax({
url: Url
type: 'POST',
data: JSON.stringify(json_data),
dataType: 'json',
cache: false,
contentType: 'application/json',
success: function (data) { Successfunction(data); },
error: function (xhr, ajaxOptions, thrownError) {
var obj = JSON.parse(xhr.responseText);
if (obj.error) {
show_errorMsg(obj.message);
}
}
});
</script>