有人可以帮我写代码吗？ 如何在文本文件中搜索任何单词并计算它重复了多少？
例如test.txt：
hi
hola
hey
hi
bye
hoola
hi
如果我想知道在 test.txt 中重复了多少次单词“Hi”，程序必须说“重复 3 次”
我希望你明白我想要什么，谢谢你的回答。
【问题讨论】：
标签： java string file search count
public class Wordcount
{
public static void main(String[] args)
{
int count=0;
String str="hi this is is is line";
String []s1=str.split(" ");
for(int i=0;i<=s1.length-1;i++)
{
if(s1[i].equals("is"))
{
count++;
}
}
System.out.println(count);
}
}
【讨论】：
public int occurrencesOfHi()
{
String newText = Text.replace("Hi","");
return (Text.length() - newText.length())/2;
}
【讨论】：
package somePackage;
public static void main(String[] args) {
String path = ""; //ADD YOUR PATH HERE
String fileName = "test2.txt";
String testWord = "Macbeth"; //CHANGE THIS IF YOU WANT
int tLen = testWord.length();
int wordCntr = 0;
String file = path + fileName;
boolean check;
try{
FileInputStream fstream = new FileInputStream(file);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
//Read File Line By Line
while((strLine = br.readLine()) != null){
//check to see whether testWord occurs at least once in the line of text
check = strLine.toLowerCase().contains(testWord.toLowerCase());
if(check){
//get the line, and parse its words into a String array
String[] lineWords = strLine.split("\\s+");
for(String w : lineWords){
//first see if the word is as least as long as the testWord
if(w.length() >= tLen){
/*
1) grab the specific word, minus whitespace
2) check to see whether the first part of it having same length
as testWord is equivalent to testWord, ignoring case
*/
String word = w.substring(0,tLen).trim();
if(word.equalsIgnoreCase(testWord)){
wordCntr++;
}
}
}
}
}
System.out.println("total is: " + wordCntr);
//Close the input stream
br.close();
} catch(Exception e){
e.printStackTrace();
}
}
【讨论】：
package com.test;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.util.Scanner;
public class Test {
public static void main(String[] args) throws Exception{
BufferedReader bf= new BufferedReader(new FileReader("src/test.txt"));
Scanner sc = new Scanner(System.in);
String W=sc.next();
//String regex ="[\\w"+W+"]";
int count=0;
//Pattern p = Pattern.compile();
String line=bf.readLine();
String s[];
do
{
s=line.split(" ");
for(String a:s)
{
if(a.contains(W))
count++;
}
line=bf.readLine();
}while(line!=null);
System.out.println(count);
}
}
【讨论】：
public int countWord(String word, File file) {
int count = 0;
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
String nextToken = scanner.next();
if (nextToken.equalsIgnoreCase(word))
count++;
}
return count;
}
【讨论】：
import java.io.*;
import java.util.*;
class filedemo
{
public static void main(String ar[])throws Exception
BufferedReader br=new BufferedReader(new FileReader("c:/file.txt"));
System.out.println("enter the string which you search");
Scanner ob=new Scanner(System.in);
String str=ob.next();
String str1="",str2="";
int count=0;
while((str1=br.readLine())!=null)
{
str2 +=str1;
}
int index = str2.indexOf(str);
while (index != -1) {
count++;
str2 = str2.substring(index + 1);
index = str2.indexOf(str);
}
System.out.println("Number of the occures="+count);
}
}
【讨论】：
package File1;
import java.io.BufferedReader;
import java.io.FileReader;
public class CountLineWordsDuplicateWords {
public static void main(String[] args) {
FileReader fr = null;
BufferedReader br =null;
String [] stringArray;
int counLine = 0;
int arrayLength ;
String s="";
String stringLine="";
try{
fr = new FileReader("F:/Line.txt");
br = new BufferedReader(fr);
while((s = br.readLine()) != null){
stringLine = stringLine + s;
stringLine = stringLine + " ";/*Add space*/
counLine ++;
}
System.out.println(stringLine);
stringArray = stringLine.split(" ");
arrayLength = stringArray.length;
System.out.println("The number of Words is "+arrayLength);
/*Duplicate String count code */
for (int i = 0; i < arrayLength; i++) {
int c = 1 ;
for (int j = i+1; j < arrayLength; j++) {
if(stringArray[i].equalsIgnoreCase(stringArray[j])){
c++;
for (int j2 = j; j2 < arrayLength; j2++) {
stringArray[j2] = stringArray[j2+1];
arrayLength = arrayLength - 1;
}
}//End of If block
}//End of Inner for block
System.out.println("The "+stringArray[i]+" present "+c+" times .");
}//End of Outer for block
System.out.println("The number of Line is "+counLine);
System.out.println();
fr.close();
br.close();
}catch (Exception e) {
e.printStackTrace();
}
}//End of main() method
}//End of class CountLineWordsDuplicateWords
【讨论】：
用Pattern 和Matcher 试试这个方法。
import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Dem {
public static void main(String[] args){
try {
File f = new File("d://My.txt");
FileReader fr = new FileReader(f);
BufferedReader br = new BufferedReader(fr);
String s = new String();
while((s=br.readLine())!=null){
s = s + s;
}
int count = 0;
Pattern pat = Pattern.compile("it*");
Matcher mat = pat.matcher(s);
while(mat.find()){
if(mat.find()){
mat.start();
count++;
}
}
System.out.println(count);
} catch (Exception e) {
e.printStackTrace();
}
}
}
【讨论】：
使用来自google guava library 的MultiSet 集合。
Multiset<String> wordsMultiset = HashMultiset.create();
Scanner scanner = new Scanner(fileName);
while (scanner.hasNextLine()) {
wordsMultiset.add(scanner.nextLine());
}
for(Multiset.Entry<String> entry : wordsMultiset ){
System.out.println("Word : "+entry.getElement()+" count -> "+entry.getCount());
}
【讨论】：
尝试使用 java.util.Scanner。
public int countWords(String w, String fileName) {
int count = 0;
Scanner scanner = new Scanner(inputFile);
scanner.useDelimiter("[^a-zA-Z]"); // non alphabets act as delimeters
String word = scanner.next();
if (word.equalsIgnoreCase(w))
count++;
return count;
}
【讨论】：
您可以逐行读取文本文件。我假设每一行可以包含多个单词。对于每一行，您调用：
String[] words = line.split(" ");
for(int i=0; i<words.length; i++){
if(words[i].equalsIgnoreCase(searhedWord))
count++;
}
【讨论】：
Apache Commons - StringUtils.countMatches()
【讨论】：
HashMap h=new HashMap();
FileInputStream fin=new FileInputStream("d:\\file.txt");
BufferedReader br=new BufferedReader(new InputStreamReader(fin));
String n;
while((n=br.readLine())!=null)
{
if(h.containsKey(n))
{
int i=(Integer)h.get(n);
h.put(n,(i+1));
}
else
h.put(n, 1);
}
现在遍历此映射以使用每个单词作为映射值的键来获取每个单词的计数
【讨论】：