【问题标题】:how to authenticate sap web service with ksoap2如何使用 ksoap2 对 sap Web 服务进行身份验证
【发布时间】:2012-04-25 13:27:03
【问题描述】:

我必须连接 SAP Web 服务。这是我的代码,但它会发出警告:

org.xmlpull.v1.XmlPullParserException:预期:START_TAG {http://schemas.xmlsoap.org/soap/envelope/}信封(位置:START_TAG @1:7 in java.io.InputStreamReader@40e3fe98)

这是我连接用户名和密码的完整代码。

final static String NAMESPACE = "urn:sap-com:document:sap:soap:functions:mc-style";
final static String METHOD_NAME = "ZmblHucremalzemelistesi";
final static String SOAP_ACTION = "";
final static String URL = "http://xxx.xxx.xxx.xxx:1080/sap/bc/srt/wsdl/bndg_4F969242EA785040E10080008D0B0B03/wsdl11/allinone/ws_policy/document?sap-client=010";


private void testWS() {
    // TODO Auto-generated method stub


    SoapObject reSoapObject = new SoapObject(NAMESPACE, METHOD_NAME);
    SoapSerializationEnvelope soaSerializationEnvelope = new SoapSerializationEnvelope(
            SoapEnvelope.VER11);

    reSoapObject.addProperty("ILgort", "H12");

    soaSerializationEnvelope.setOutputSoapObject(reSoapObject);
    soaSerializationEnvelope.headerOut = new Element[1]; 
    soaSerializationEnvelope.headerOut[0] = buildAuthHeader(); 

    HttpTransportSE httpTransportSE = new HttpTransportSE(URL);

    try {

        httpTransportSE.call(SOAP_ACTION, soaSerializationEnvelope);

        Object response = soaSerializationEnvelope.getResponse();

        tv.setText(response.toString());

    } catch (IOException e) {
        e.printStackTrace();
    } catch (XmlPullParserException e) {
        e.printStackTrace();
    }


}

private Element buildAuthHeader() { 

    Element h = new Element().createElement(NAMESPACE, "AuthHeader"); 
    Element username = new Element().createElement(NAMESPACE, "user"); 
    username.addChild(Node.TEXT, "testuser"); 
    h.addChild(Node.ELEMENT, username); 
    Element pass = new Element().createElement(NAMESPACE, "pass"); 
    pass.addChild(Node.TEXT, "testpwd"); 
    h.addChild(Node.ELEMENT, pass); 

    return h; 
} 

【问题讨论】:

  • 我用这个帖子来实现但没有解决stackoverflow.com/questions/5613675/…
  • 当我将 URL 设置为我的 WSDL url 时,我只得到 anyType{} 结果
  • 以及当我替换对象响应时.. 线 SoapObject response = (SoapObject)soaSeria.. 我得到了 ZmblHucremalzemelistesiResponse{THcrmlzlist=anyType{}; } 结果:S
  • ,我遇到了同样的问题,我在这里找到了解决方案stackoverflow.com/questions/51255957/…你可以按照我的整个代码并获得解决方案..

标签: java android web-services sap ksoap2


【解决方案1】:

试试这个:

final static String NAMESPACE = "urn:sap-com:document:sap:soap:functions:mc-style";
    final static String METHOD_NAME = "ZmblHucremalzemelistesi";
    final static String SOAP_ACTION = "";
    final static String URL = "http://xxx.xxx.xxx.xxx:1080/sap/bc/srt/wsdl/bndg_4F969242EA785040E10080008D0B0B03/wsdl11/allinone/ws_policy/document?sap-client=010";

    private static final String USERNAME = "YOUR_USERNAME";
    private static final String PASSWORD = "YOUR_PASSWORD";

    private void testWS() {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        request.addProperty("ILgort", "H12");

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.setOutputSoapObject(request);

        AuthTransportSE androidHttpTransport = new AuthTransportSE(URL, USERNAME, PASSWORD);
        androidHttpTransport.debug = true;

        try {
            androidHttpTransport.call(SOAP_ACTION, envelope);
            SoapObject response = (SoapObject) envelope.getResponse();
            // if it did not work, try this:
            // SoapObject response = (SoapObject) envelope.bodyIn;

            tv.setText(response.toString());

        } catch (IOException e) {
            e.printStackTrace();
        }
    }

而 AuthTransportSE 类是:

import java.io.IOException;

import org.ksoap2.transport.HttpTransportSE;
import org.ksoap2.transport.ServiceConnection;
import org.ksoap2.transport.ServiceConnectionSE;

public class AuthTransportSE extends HttpTransportSE{
    private String username;
    private String password;

    public AuthTransportSE(String url, String username, String password) {
        super(url);
        this.username = username;
        this.password = password;       
    }

    protected ServiceConnection getServiceConnection() throws IOException {
        ServiceConnection midpConnection = new ServiceConnectionSE(url);
        addBasicAuthentication(midpConnection);
        return midpConnection;
    }

    protected void addBasicAuthentication(ServiceConnection midpConnection) throws IOException {
        if (username != null && password != null) {
            StringBuffer buf = new StringBuffer(username);
            buf.append(':').append(password);
            byte[] raw = buf.toString().getBytes();
            buf.setLength(0);
            buf.append("Basic ");
            org.kobjects.base64.Base64.encode(raw, 0, raw.length, buf);
            midpConnection.setRequestProperty("Authorization", buf.toString());
        }
    }
}

【讨论】:

  • 感谢您的回复,我尝试了 bodyIn 和 getResponse() 但是,我得到了结果:ZmblHucremalzemelistesiResponse{THcrmlzlist=anyType{}; } 仍然没有解决:(
  • 如果你能看到这个:ZmblHucremalzemelistesiResponse{THcrmlzlist=anyType{};您现在可以访问网络服务。您是否尝试使用具有相同参数的 SOAP 客户端程序测试此服务?
  • 这里是最后一个详细错误:SoapFault - faultcode: 'soap-env:Server' faultstring: 'CX_ST_MATCH_ELEMENT:XSLT Exception aufgetreten.Element 'ILgort' erwartet' faultactor: 'null' detail: org. kxml2.kdom.Node@40e845f8
猜你喜欢
  • 2011-04-22
  • 1970-01-01
  • 2011-10-28
  • 2012-07-28
  • 1970-01-01
  • 1970-01-01
  • 2014-06-08
  • 1970-01-01
  • 1970-01-01
相关资源
最近更新 更多