【发布时间】:2014-09-15 21:53:36
【问题描述】:
我使用 jax-rs 和 jersey 创建了一个 REST Web 服务,它应该在 POST 请求上使用 JSON。我的网络服务类如下所示:
@Path("/webhookservice")
public class Webhook {
@POST
@Consumes(MediaType.APPLICATION_JSON)
public Response readData (Song song) {
// Prints out the song info
System.out.println("SONG INFO \n=======================");
System.out.println("songname: " + song.getSongname());
System.out.println("artist: " + song.getArtist());
// Repsonse with a HTTP 200 OK
Response response = Response.status(200).build();
return response;
}
}
我的歌曲课:
public class Song {
private String songname;
private String artist;
public String getSongname () { return this.songname; }
public String getArtist () { return this.artist; }
public void setSongname (String songname) { this.songname = songname; }
public void setArtist (String artist) { this.artist = artist; }
}
我的 web.xml(如果需要)
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<servlet>
<servlet-name>SnapScan-Webhook</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>za.co.lancet.service</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SnapScan-Webhook</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
我正在使用RESTClient 一点,好吧,休息客户端...这是我发送的内容的屏幕截图:
当我发送它时,我收到 415 Unsupported Media Type 错误。有人知道为什么吗?
【问题讨论】:
-
客户端是否发送标头
Content-Type: application/json? -
你知道你可能是对的。让我看看
-
@lefloh - 你是赢家!你是对的,我什至不知道你需要在这些小客户端应用程序中设置它。您可以发布作为答案,我会接受。谢谢!
标签: java json rest jersey jax-rs