【发布时间】:2017-08-17 07:03:50
【问题描述】:
当我在 tinymce 中添加图像时,这是我得到的默认 html 源代码:
<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p>
我该如何改变?类似于:
<p><img class="img-responsive img-post" data-original="/Images/uploads/img.png" src="/Images/loading.gif" alt="" /></p>
我有 data-original 作为 src 并且 src 是加载图标,它需要是这样的,因为我对图像进行了延迟加载。
我知道您可以使用以下方法扩展有效元素:
extend_valid_elements: "data-original"
但是如何更改默认 html 源代码的结构?是否有类似选择 ok 进行图像插入回调的事情?
更新:
这是我的 tinymce 启动代码:
/******************************tinyMce*******************************/
function tinyMce() {
tinymce.init({
theme: "modern",
selector: "#mceEditor",
height: 500,
extend_valid_elements: "data-original",
relative_urls: true,
convert_urls: false,
image_advtab: true,
image_title: false,
image_description: false,
image_dimensions: false,
image_class_list: [
{ title: "Responsive", value: "lazy img-responsive img-post" }
],
image_list: function (success) {
$.ajax({
url: "/Image/List",
type: "GET",
dataType: "json",
success: function (data) {
success(data);
}
});
},
// enable automatic uploads of images represented by blob or data URIs
automatic_uploads: true,
// URL of our upload handler (for more details check: https://www.tinymce.com/docs/configure/file-image-upload/#images_upload_url)
images_upload_url: "/Image/Upload",
// here we add custom filepicker only to Image dialog
file_picker_types: "image",
// and here's our custom image picker
file_picker_callback: function (cb, value, meta) {
var input = document.createElement("input");
input.setAttribute("type", "file");
input.setAttribute("accept", "image/*");
// Note: In modern browsers input[type="file"] is functional without
// even adding it to the DOM, but that might not be the case in some older
// or quirky browsers like IE, so you might want to add it to the DOM
// just in case, and visually hide it. And do not forget do remove it
// once you do not need it anymore.
input.onchange = function () {
var file = this.files[0];
var reader = new FileReader();
reader.readAsDataURL(file);
reader.onload = function () {
// Note: Now we need to register the blob in TinyMCEs image blob
// registry. In the next release this part hopefully won't be
// necessary, as we are looking to handle it internally.
var id = "blobid" + (new Date()).getTime();
var blobCache = tinymce.activeEditor.editorUpload.blobCache;
var base64 = reader.result.split(',')[1];
var blobInfo = blobCache.create(id, file, base64);
blobCache.add(blobInfo);
// call the callback and populate the Title field with the file name
cb(blobInfo.blobUri(), { title: file.name });
};
};
input.click();
}
});
}
我现在正在考虑另一种方法,如果我可以将tinymce中的默认src属性替换为data-original,那就完美了,但是在tinymce内部,如果我使用data-original,它就不会显示图片,它justs 显示空白。有没有办法在添加图像时告诉 tinymce,放置 data-original 而不是 src 并从 data-original 读取而不是 src?
因此:
<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p>
完全没有 src 的情况:
<p><img class="img-responsive img-post" data-original="/Images/uploads/img.png" alt="" /></p>
【问题讨论】:
-
您可能会发现在延迟加载代码加载后添加图像可能无法检测到它们。因此,如果您排除
src属性,它将根本不会显示图像。 -
@KScandrett 它会显示
-
谢谢,但我已经读过了,上传已经完成,这不是我想要的
标签: jquery html css tinymce jquery-lazyload