在android中解析json对象时出错[重复]答案

【问题标题】：error in parsing json object in android [duplicate]在android中解析json对象时出错[重复]
【发布时间】：2016-05-25 01:43:28
【问题描述】：

我在 Internet 上看到此代码并按照那里的步骤操作然后我 bulif .php 文件和 phpmyadmin 数据库然后我测试它们连接成功的 php 文件抛出 Web 浏览器，Web 浏览器 php 测试的结果显示为 @987654321 @。

public class SignupActivity extends AsyncTask<String, Void, String> {

    private Context context;

    public SignupActivity(Context context) {
        this.context = context;
    }

    protected void onPreExecute() {

    }

    @Override
    protected String doInBackground(String... arg0) {
        String fullName = arg0[0];
        String userName = arg0[1];
        String passWord = arg0[2];
        String phoneNumber = arg0[3];
        String emailAddress = arg0[4];

        String link;
        String data;
        BufferedReader bufferedReader;
        String result;

        try {
            data = "?fullname=" + URLEncoder.encode(fullName, "UTF-8");
            data += "&username=" + URLEncoder.encode(userName, "UTF-8");
            data += "&password=" + URLEncoder.encode(passWord, "UTF-8");
            data += "&phonenumber=" + URLEncoder.encode(phoneNumber, "UTF-8");
            data += "&emailaddress=" + URLEncoder.encode(emailAddress, "UTF-8");

            link = "http://testandroid.netai.net/signup.php" + data;
            URL url = new URL(link);
            HttpURLConnection con = (HttpURLConnection) url.openConnection();

            bufferedReader = new BufferedReader(new InputStreamReader(con.getInputStream()));
            result = bufferedReader.readLine();
            return result;
        } catch (Exception e) {
            return new String("Exception: " + e.getMessage());
        }
    }

    @Override
    protected void onPostExecute(String result) {
        String jsonStr = result;
        if (jsonStr != null) {
            try {
                JSONObject jsonObj = new JSONObject(jsonStr);
                String query_result = jsonObj.getString("query_result");
                if (query_result.equals("SUCCESS")) {
                    Toast.makeText(context, "Data inserted successfully. Signup successfull.", Toast.LENGTH_SHORT).show();
                } else if (query_result.equals("FAILURE")) {
                    Toast.makeText(context, "Data could not be inserted. Signup failed.", Toast.LENGTH_SHORT).show();
                } else {
                    Toast.makeText(context, "Couldn't connect to public class SignupActivity extends AsyncTask<String, Void, String> {

    private Context context;

    public SignupActivity(Context context) {
        this.context = context;
    }

    protected void onPreExecute() {

    }

    @Override
    protected String doInBackground(String... arg0) {
        String fullName = arg0[0];
        String userName = arg0[1];
        String passWord = arg0[2];
        String phoneNumber = arg0[3];
        String emailAddress = arg0[4];

        String link;
        String data;
        BufferedReader bufferedReader;
        String result;

        try {
            data = "?fullname=" + URLEncoder.encode(fullName, "UTF-8");
            data += "&username=" + URLEncoder.encode(userName, "UTF-8");
            data += "&password=" + URLEncoder.encode(passWord, "UTF-8");
            data += "&phonenumber=" + URLEncoder.encode(phoneNumber, "UTF-8");
            data += "&emailaddress=" + URLEncoder.encode(emailAddress, "UTF-8");

            link = "http://testandroid.netai.net/signup.php" + data;
            URL url = new URL(link);
            HttpURLConnection con = (HttpURLConnection) url.openConnection();

            bufferedReader = new BufferedReader(new InputStreamReader(con.getInputStream()));
            result = bufferedReader.readLine();
            return result;
        } catch (Exception e) {
            return new String("Exception: " + e.getMessage());
        }
    }

    @Override
    protected void onPostExecute(String result) {
        String jsonStr = result;
        if (jsonStr != null) {
            try {
                JSONObject jsonObj = new JSONObject(jsonStr);
                String query_result = jsonObj.getString("query_result");
                if (query_result.equals("SUCCESS")) {
                    Toast.makeText(context, "Data inserted successfully. Signup successfull.", Toast.LENGTH_SHORT).show();
                } else if (query_result.equals("FAILURE")) {
                    Toast.makeText(context, "Data could not be inserted. Signup failed.", Toast.LENGTH_SHORT).show();
                } else {
                    Toast.makeText(context, "Couldn't connect to remote database.", Toast.LENGTH_SHORT).show();
                }
            } catch (JSONException e) {
                e.printStackTrace();
                Toast.makeText(context, "Error parsing JSON data.", Toast.LENGTH_SHORT).show();
            }
        } else {
            Toast.makeText(context, "Couldn't get any JSON data.", Toast.LENGTH_SHORT).show();
        }
    }
}

【问题讨论】：

在 android 中总是向我显示解析 JSON 数据时出错

标签： java php android json android-asynctask

【解决方案1】：

先试试这个

            JSONObject jsonObj = new JSONObject(jsonStr);
            String query_result = jsonObj.getString("query_result");
            if (query_result.equals("success")) {
                Toast.makeText(context, "Data inserted successfully. Signup successfull.", Toast.LENGTH_SHORT).show();
            } else if (query_result.equals("failure")) {
                Toast.makeText(context, "Data could not be inserted. Signup failed.", Toast.LENGTH_SHORT).show();
            }

【讨论】：