在 Textview 中获取响应、Url 和 Url 代码

Question

我正在尝试向 url 发出 post 请求，并获取显示在 TextView 中的 URL、响应代码和响应。我能够在日志中获取 URL 和响应代码，但无法获取响应。 请检查代码并告诉如何在TextView 中打印所有三个 谢谢

import java.io.BufferedReader;
import java.io.DataOutputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.widget.TextView;
public class MainActivity extends Activity {

String rescode,urlcode,responsecode;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    new LongOperation().execute("");
}

private class LongOperation extends AsyncTask<String, Void, String> {

    @Override
    protected String doInBackground(String... params) {
        try {
            String url = "http://google.com";
            URL obj = new URL(url);
            HttpURLConnection con = (HttpURLConnection) obj
                    .openConnection();



            // Send post request
            con.setDoOutput(true);
            DataOutputStream wr = new DataOutputStream(
                    con.getOutputStream());

            wr.flush();
            wr.close();

            int responseCode = con.getResponseCode();

        ////////////////////////////////////////////////////////////////
            /*TextView tv2 = (TextView) findViewById(R.id.textView2);
            TextView tv3 = (TextView) findViewById(R.id.textView3);

            urlcode = url.getBytes().toString();
            rescode = responsecode.getBytes().toString();

            tv2.getText().toString();
            tv2.setText("URL-  "+urlcode);
            tv3.setText("ResponseCode-  "+rescode);*/

        /////////////////////////////////////////////////////////////////// 


            System.out.println("\nSending 'POST' request to URL : -----------------------" + url);
    //      System.out.println("Post parameters : " + urlParameters);
            System.out.println("Response Code : -------------------------------" + responseCode);


            BufferedReader in = new BufferedReader(new InputStreamReader(
                    con.getInputStream()));
            String inputLine;
            StringBuffer response = new StringBuffer();

            while ((inputLine = in.readLine()) != null) {
                response.append(inputLine);
            }
            in.close();

            // print result
            System.out.println("+++++++++"+response.toString());
        //  System.out.println("Response" +response);
            TextView tv = (TextView) findViewById(R.id.textView1);
            rescode = response.toString();

            tv.setText("aa"+rescode);
            return response.toString();

        } catch (Exception e) {
            System.out
                    .println("MainActivity.LongOperation.doInBackground()"+e);

        }
        return null;

    }

    @Override
    protected void onPostExecute(String result) {

    }

    @Override
    protected void onPreExecute() {
    }

    @Override
    protected void onProgressUpdate(Void... values) {
    }
}
}

日志

05-09 16:09:59.642: I/System.out(16309): Sending 'POST' request to URL : ---------------http://google.com

05-09 16:09:59.652: I/System.out(16309): Response Code : ------------------------------405

    050916:09:59.652:I/System.out(16309):MainActivity.LongOperation.doInBackground()java.io.FileNotFoundException: http://google.com

Answer 1

不要从 doInBackground 方法访问 UI

试试下面的

 private class LongOperation extends AsyncTask<String, Void, String> {

@Override
protected String doInBackground(String... params) {
    try {
        String url = "http://google.com";
        URL obj = new URL(url);
        HttpURLConnection con = (HttpURLConnection) obj
                .openConnection();



        // Send post request
        con.setDoOutput(true);
        DataOutputStream wr = new DataOutputStream(
                con.getOutputStream());

        wr.flush();
        wr.close();

        int responseCode = con.getResponseCode();

    ////////////////////////////////////////////////////////////////
        /*TextView tv2 = (TextView) findViewById(R.id.textView2);
        TextView tv3 = (TextView) findViewById(R.id.textView3);

        urlcode = url.getBytes().toString();
        rescode = responsecode.getBytes().toString();

        tv2.getText().toString();
        tv2.setText("URL-  "+urlcode);
        tv3.setText("ResponseCode-  "+rescode);*/

    /////////////////////////////////////////////////////////////////// 


        System.out.println("\nSending 'POST' request to URL : -----------------------" + url);
//      System.out.println("Post parameters : " + urlParameters);
        System.out.println("Response Code : -------------------------------" + responseCode);


        BufferedReader in = new BufferedReader(new InputStreamReader(
                con.getInputStream()));
        String inputLine;
        StringBuffer response = new StringBuffer();
       if(in!=null){
           while ((inputLine = in.readLine()) != null) {
            response.append(inputLine);
          }
        in.close();
       }

        // print result
        System.out.println("+++++++++"+response.toString());
    //  System.out.println("Response" +response);

        rescode = response.toString();


        return response.toString();

    } catch (Exception e) {
        System.out
                .println("MainActivity.LongOperation.doInBackground()"+e);

    }
    return null;

}

@Override
protected void onPostExecute(String result) {
    tv.setText("aa"+result);
}

@Override
protected void onPreExecute() {
}

@Override
protected void onProgressUpdate(Void... values) {
}
}
}