【发布时间】:2015-06-21 05:21:45
【问题描述】:
我实际上是 Java 编程的新手,但我一直在关注我的问题的几种解决方案,但没有找到适合我情况的解决方案,而且我似乎无法正确获取代码。
我想要一个 WebView,它在手机在线时打开一个在线页面(例如 google),在手机离线时打开一个本地 html 页面。
同时,虽然我希望手机在在线时覆盖本地页面,以便离线本地页面始终更新到手机最后一次连接到互联网时。
任何想法如何做到这一点?一些简单的指向正确的方向可能会有所帮助。
非常感谢
我的源代码
WebView engine=(WebView)findViewById(R.id.webView);
engine.getSettings().setJavaScriptEnabled(true);
engine.getSettings().setBuiltInZoomControls(true);
engine.getSettings().setLoadsImagesAutomatically(true);
engine.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);
engine.setInitialScale(1);
engine.setWebChromeClient(new WebChromeClient() {
@Override
public void onReachedMaxAppCacheSize(long spaceNeeded, long totalUsedQuota,QuotaUpdater quotaUpdater)
{
quotaUpdater.updateQuota(spaceNeeded * 2);
}
public void onProgressChanged(WebView view, int progress)
{
activity.setTitle("Loading...");
activity.setProgress(progress * 100);
if(progress == 100)
{ activity.setTitle(R.string.app_name);
}
}
});
engine.getSettings().setDomStorageEnabled(true);
// Set cache size to 8 mb by default. should be more than enough
engine.getSettings().setAppCacheMaxSize(1);
engine.getSettings().setAllowFileAccess(true);
engine.getSettings().setAppCacheEnabled(true);
engine.getSettings().setCacheMode(WebSettings.LOAD_DEFAULT);
Map<String, String> noCacheHeaders = new HashMap<String, String>(2);
noCacheHeaders.put("Pragma", "no-cache");
noCacheHeaders.put("Cache-Control", "no-cache");
// engine.loadUrl("http://www.stackhand.com", noCacheHeaders);
cm = (ConnectivityManager) this.getSystemService(Activity.CONNECTIVITY_SERVICE);
if(cm.getActiveNetworkInfo().isConnected())
{
engine.getSettings().setCacheMode(WebSettings.LOAD_DEFAULT);
}
else{
engine.getSettings().setCacheMode(WebSettings.LOAD_CACHE_ELSE_NETWORK);
}
engine.loadUrl("http://www.stackhand.com", noCacheHeaders);
使用此功能检查网络在线和离线
private boolean isNetworkAvailable() {
ConnectivityManager connectivityManager = (ConnectivityManager)
getSystemService( CONNECTIVITY_SERVICE );
NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
return activeNetworkInfo != null && activeNetworkInfo.isConnected();
}
【问题讨论】: