WebView - 打开 target=_blank 链接作为 target=_self答案

【问题标题】：WebView - open target=_blank links as target=_selfWebView - 打开 target=_blank 链接作为 target=_self
【发布时间】：2018-09-17 14:06:24
【问题描述】：

我的应用程序使用 webview 加载站点。一些链接有目标_blank并在新窗口中打开

public class EkChromeViewClient extends android.webkit.WebChromeClient {
    @Override
    public boolean onCreateWindow(WebView view, boolean isDialog, boolean isUserGesture, Message resultMsg) {
        Log.d("!!!new window!!!", "yes");

        WebView newWebView = new WebView(view.getContext());
        newWebView.getSettings().setPluginState(WebSettings.PluginState.ON);
        newWebView.getSettings().setDomStorageEnabled(true);
        newWebView.getSettings().setSupportMultipleWindows(true);
        newWebView.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);

        newWebView.setWebViewClient(new EkWebViewClient());

        view.addView(newWebView);
        WebView.WebViewTransport transport = (WebView.WebViewTransport) resultMsg.obj;
        transport.setWebView(newWebView);
        resultMsg.sendToTarget();

        return true;
    }

    @Override
    public void onCloseWindow(WebView window) {
        Log.d("!!!close window!!!", "yes");
        super.onCloseWindow(window);
    }
}

但我只需要在一个窗口中打开所有 url，忽略 target=_blank

【问题讨论】：

标签： android webview

【解决方案1】：

你需要做这样的事情。

webView.setWebChromeClient(new WebChromeClient() {
@Override
        public boolean onCreateWindow(WebView view, boolean isDialog, boolean isUserGesture, Message resultMsg) {
            Uri parsedUri = Uri.parse(view.getUrl());
            WebView newWebView = new WebView(view.getContext());
            view.addView(newWebView);
            WebView.WebViewTransport transport = (WebView.WebViewTransport) resultMsg.obj;
            transport.setWebView(newWebView);
            resultMsg.sendToTarget();
            PackageManager packageManager = getPackageManager();
            Intent browseIntent = new Intent(Intent.ACTION_VIEW).setData(parsedUri);
            if (browseIntent.resolveActivity(packageManager) != null) {
                startActivity(browseIntent);
                return true;
            }
            return true;
        }
    });

【讨论】：