【问题标题】:Unable to Load Simple ListView In Android Fragment无法在 Android 片段中加载简单的 ListView
【发布时间】:2014-03-01 11:54:02
【问题描述】:

我有一个片段包含列表视图、按钮和图像。按钮、图像和其他小部件已正确加载,但不是列表视图,它只显示加载图标

公共类 ListDetails 扩展 SherlockFragment{

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        // TODO Auto-generated method stub
         ListView listView = (ListView)container.findViewById(R.id.list_view2);

            // Defined Array values to show in ListView
            String[] values = new String[] { "Android List View", 
                                             "Adapter implementation",
                                             "Simple List View In Android",
                                             "Create List View Android", 
                                             "Android Example", 
                                             "List View Source Code", 
                                             "List View Array Adapter", 
                                             "Android Example List View" 
                                            };

            // Define a new Adapter
            // First parameter - Context
            // Second parameter - Layout for the row
            // Third parameter - ID of the TextView to which the data is written
            // Forth - the Array of data

            ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity().getApplicationContext(),android.R.layout.simple_list_item_1, android.R.id.text1, values);


            // Assign adapter to ListView
            listView.setAdapter(adapter); 
        return inflater.inflate(
                R.layout.listdetails_fragement, container, false);
    }

我检查了其他按钮,图像已加载,但列表视图在我的 ArrayAdapter&lt;String&gt; adapter = new ArrayAdapter&lt;String&gt;(getActivity().getApplicationContext(),android.R.layout.simple_list_item_1, android.R.id.text1, values); 行 上出现错误

这里我提供了我的 logcat 错误。

【问题讨论】:

    标签: android android-listview android-fragments actionbarsherlock android-listfragment


    【解决方案1】:

    这就是我所做的:

    我没有在 onCreateView() 中执行所有操作,而是使用了 onActivityCreated()。

    在onActivityCreated()中,我刚刚添加了这段代码:下面是实现:

    public class Database extends Fragment {
    
        public ViewPager viewPager;
        private AllPagesAdapter mAdapter;
        private ActionBar actionBar;
        private String[] tabs = { "Tab1", "Tab2" };
        String[] values = new String[] { "Android List View", 
                "Adapter implementation",
                "Simple List View In Android",
                "Create List View Android", 
                "Android Example", 
                "List View Source Code", 
                "List View Array Adapter", 
                "Android Example List View" 
               };
        ArrayAdapter<String> mArrayAdapter; 
    
        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container,
                Bundle savedInstanceState) {
    
            View databaseview = inflater.inflate(R.layout.database, container,
                    false);
    
    
    
            return databaseview;
    
        }
    
        @Override
        public void onActivityCreated(Bundle savedInstanceState) {
            // TODO Auto-generated method stub
            super.onActivityCreated(savedInstanceState);
    
            ListView mListView = (ListView)getActivity().findViewById(R.id.databaselist);
    
            mArrayAdapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_list_item_1, android.R.id.text1, values);
    
            mListView.setAdapter(mArrayAdapter);
    
        }
    
    }
    

    我使用的布局是:

    <?xml version="1.0" encoding="utf-8"?>
    <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
    
        android:orientation="vertical" >
    
        <LinearLayout
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:orientation="vertical" >
        </LinearLayout>
    
        <ListView
            android:id="@+id/databaselist"
            android:layout_width="match_parent"
            android:layout_height="254dp" >
        </ListView>
    
        <TextView
            android:id="@+id/newmainlist"
            android:layout_width="match_parent"
            android:layout_height="250dp"
            android:gravity="center"
            android:text="database" />
    
    </LinearLayout>
    

    另外,这是它的图片:

    希望这会有所帮助.. :)

    【讨论】:

      【解决方案2】:

      因为这条线的错误..

      ListView listView = (ListView)container.findViewById(R.id.list_view2);
      

      这里listview 为空 像这样更改您的代码..

      @Override
      public View onCreateView(LayoutInflater inflater, ViewGroup container,
              Bundle savedInstanceState) {
          // TODO Auto-generated method stub
          View view = inflater.inflate(R.layout.listdetails_fragement, container,
                  false);
      
          ListView listView = (ListView) view.findViewById(R.id.list_view2);
      
          // Defined Array values to show in ListView
          String[] values = new String[] { "Android List View",
                  "Adapter implementation", "Simple List View In Android",
                  "Create List View Android", "Android Example",
                  "List View Source Code", "List View Array Adapter",
                  "Android Example List View" };
      
          // Define a new Adapter
          // First parameter - Context
          // Second parameter - Layout for the row
          // Third parameter - ID of the TextView to which the data is written
          // Forth - the Array of data
      
          ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity()
                  .getApplicationContext(), android.R.layout.simple_list_item_1,
                  android.R.id.text1, values);
      
          // Assign adapter to ListView
          listView.setAdapter(adapter);
          return view;
      }
      

      【讨论】:

      • 那么getActivity().getApplicationContext() in adapter 是否有效?
      • @SimplePlan 是的,它可以工作..它返回父 Activity 上下文
      • @kalyanpvs 那么 getActivity() 呢?
      • @SimplePlan 是要添加该片段的父 Activity 对象。如果它的名称是 MainActivity 则 getActivity() 返回 MainActivity 对象
      • @kalyanpvs 这就是我所说的,所以这两种解决方案都在这里工作。thnx
      【解决方案3】:

      用这个改变onCreateView(....)

       @Override
      public View onCreateView(LayoutInflater inflater, ViewGroup container,
              Bundle savedInstanceState) {
          // TODO Auto-generated method stub
           View v=inflater.inflate(
                  R.layout.listdetails_fragement, container, false);
      
           ListView listView = (ListView)v.findViewById(R.id.list_view2);
      
              // Defined Array values to show in ListView
              String[] values = new String[] { "Android List View", 
                                               "Adapter implementation",
                                               "Simple List View In Android",
                                               "Create List View Android", 
                                               "Android Example", 
                                               "List View Source Code", 
                                               "List View Array Adapter", 
                                               "Android Example List View" 
                                              };
      
      
              ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity().getApplicationContext(),android.R.layout.simple_list_item_1, android.R.id.text1, values);
      
      
              // Assign adapter to ListView
              listView.setAdapter(adapter); 
          return v;
      }
      

      【讨论】:

      • 我试过了,但它给了我同样的错误。:(还有其他解决方案吗?
      • java.lang.RuntimeException:无法启动活动 ComponentInfo{com.androidhive.androidlistviewwithsearch/com.androidhive.androidlistviewwithsearch.MainActivity}:java.lang.NullPointerException
      • 好吧,你的 onCreateView(...) 也出错了,用我的回答吧
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