【发布时间】:2014-09-09 11:59:46
【问题描述】:
我想使用异步任务将项目添加到listview中,所以在doinbackgroud中它会一一处理并获取数据,然后将其一一显示在listview上。 但是对于我的应用,doinbackground 处理所有数据,然后它将显示到列表视图中。
public class NewGetContacts extends AsyncTask<String[], Void, Void> {
private static final String TAG_TX = "txid";
private static final String TAG_FEE = "fees";
MyCustomAdapter mAdapter=new MyCustomAdapter();
ListView listViewHandle1 = (ListView) findViewById(R.id.listView2);
@Override
protected Void doInBackground(String[]... params) {
// TODO Auto-generated method stub
int len = params[0].length;
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
// String jsonStr;
mAdapter.addSeparatorItem("Transaction ...");
for(int i=0;i<len ;i++){
String turl = "https://coin/api/tx/"+params[0][i];
try {
String jsonStr1 = sh.makeServiceCall(turl, ServiceHandler.GET);
JSONObject jsonObj2 = new JSONObject(jsonStr1);
txtid = jsonObj2.getString(TAG_TX);
mAdapter.addItem("Transaction ID : "+txtid);
publishProgress();
}catch(Exception e){
Log.d("Exception In TXID -- >",e.getMessage());
}
}
return null;
}
protected void onProgressUpdate(Void... r) {
super.onProgressUpdate(r);
Log.d("Txid 14546465 ","--->");
mAdapter.notifyDataSetChanged();
listViewHandle1.requestLayout();
super.onProgressUpdate(r);
}
protected void onPostExecute(Void result) {
super.onPostExecute(result);
listViewHandle1.setAdapter(mAdapter);
mAdapter.notifyDataSetChanged();
}
}
【问题讨论】:
标签: android android-listview baseadapter