RecyclerView 中的两个对象类型，每个对象类型都有自己的 ViewHolder

Question

我正在尝试创建 recyclerview，它显示来自一个对象 (ObjectMaster) 的两个不同数组的结果。我不太关心顺序，只要两个数组都显示在列表中即可。任何想法或建议将不胜感激。

型号

public ObjectMaster {
  List<Object1> first_objects;
  List<Object2> second_objects;
}

适配器

public class ObjectMasterAdapter extends RecyclerView.Adapter<RecyclerView.ViewHolder> {

 private ObjectMaster object;
 private static final int TYPE_OBJECT1 = 0;
 private static final int TYPE_OBJECT2 = 1;

 public ObjectMasterAdapter(ObjectMaster object) {
  this.object = object;
}

public class Object1Holder extends RecyclerView.ViewHolder {
  private TextView title;
  private TextView subtitle;

  public Object1Holder(View itemView) {
   super(itemView);
   title = (TextView) itemView.findViewById(R.id.title);
   subtitle = (TextView) itemView.findViewById(R.id.subtitle);
  }
  public void bindObj(Object1 object) {
    title.setText(object.getTitle());
    subtitle.setText(object.getSubtitle());
  }
}
public class Object2Holder extends RecyclerView.ViewHolder {
  private TextView title;

  public Object2Holder(View itemView) {
   super(itemView);
   title = (TextView) itemView.findViewById(R.id.title);
  }
  public void bindObj(Object2 object) {
    title.setText(object.getTitle());
  }
}

 @Override
 public int getItemViewType(int position) {

  // I need to figure out the best way to determine if its already listed objects from the first object array (Object1)
 }

 @Override
 public RecyclerView.ViewHolder onCreateViewHolder(ViewGroup viewGroup, int i) {

  View view = LayoutInflater.from(viewGroup.getContext()).inflate(R.layout.object_item, viewGroup, false);
  switch(i) {
   case TYPE_OBJECT1: return new Object1Holder(view);
   case TYPE_OBJECT2: return new Object2Holder(view);
  }
  return null;
}

 public void onBindViewHolder(RecyclerView.ViewHolder viewHolder, int i) {

    switch (viewHolder.getItemViewType()) {
        case TYPE_OBJECT1:
            Object1Holder object1 = (Object1Holder) viewHolder;
            object1.bindObj(object.first_objects.get(i));
            break;

        case TYPE_OBJECT2:
            Object2Holder object2 = (Object2Holder) viewHolder;
            object2.bindObj(object.second_objects.get(i));
            break;
    }
 }

 @Override
 public int getItemCount() {
     return object.first_objects.size() + object.second_objects.size();
 }

Answer 1

我需要找出最好的方法来确定它是否已经从第一个对象数组（Object1）中列出了对象

如果position 大于（或等于）第一个数组的长度，则您现在进入第二个数组。从position 中减去第一个数组的长度，得到第二个数组的索引。

还请注意，onBindViewHolder() 中有一个错误，因为当它是第二个数组时，您没有执行类似的减法来将 position（i 值）更改为第二个数组的索引您正在处理的数组的视图类型。