【发布时间】:2020-01-18 14:07:39
【问题描述】:
所以我制作了一个“记事本”应用程序,并且我想要保存用户写的文本等它应该被保存,所以当用户退出应用程序时文本不会被重置。
我是 react-native 的新手,经过几次谷歌搜索后,我需要 AsyncStorage?实现这一目标。 但真的不知道该怎么做。
import React, { useState } from 'react';
import {
StyleSheet,
Text,
View,
FlatList,
TouchableWithoutFeedback,
TouchableOpacity,
Keyboard,
AsyncStorage
} from 'react-native';
import Header from './components/header';
import ListItem from './components/listitem';
import AddList from './components/addlist';
export default function App() {
const [todos, setTodos] = useState([
]);
const pressHandler = (key) => {
setTodos((prevTodos) => {
return prevTodos.filter(todo => todo.key != key);
});
}
const submitHandler = (text) => {
if(text.length > 0) {
setTodos((prevTodos) => {
return [
{ text: text, key: Math.random().toString() },
...prevTodos
];
})
}
}
return (
<TouchableWithoutFeedback onPress={() => {
Keyboard.dismiss();
}}>
<View style={styles.container}>
<Header />
<View style={styles.content}>
<AddList submitHandler={submitHandler} />
<View style={styles.todoList}>
<FlatList
data={todos}
renderItem={({ item }) => (
<ListItem item={item} pressHandler={pressHandler} />
)}
/>
</View>
</View>
</View>
</TouchableWithoutFeedback>
);
}
突然出现的新问题在没有接触代码的情况下就被破解了
const pressHandler = key =>
setTodos(prevTodos => {
const newTodos = prevTodos.filter(todo => todo.key !== key);
storeTodosInAsync(newTodos);
console.log(prevTodos);
return newTodos;
});
const submitHandler = text => {
if (text.length > 0) {
const key = Math.random().toString();
setTodos(prevTodos => {
const newTodos = [{ text, key }, ...prevTodos];
storeTodosInAsync(newTodos);
console.log(newTodos);
return newTodos;
});
}
};
【问题讨论】: