【问题标题】:Saving history of drawing in Pygame in order to implement Ctrl Z在 Pygame 中保存绘图历史以实现 Ctrl Z
【发布时间】:2020-04-18 20:30:41
【问题描述】:

我试图记住以前的图纸来实现 Ctrl-Z(撤消)和(重做)。为此,我使用集合中的堆栈(deque),我还创建了一个名为 DrawEntity 的对象,它具有矩形列表(pygame 类)的属性,因为我不想保存 every 我绘制的像素,但只有一个“笔触”而不是构成他的组件(小 ractangles 笔触)但是,我不知道如何插入到主 DrawEntity 列表中,这会将这些实体保存在每个笔触的队列,而不是每个矩形的队列。这是我到目前为止所拥有的:

main.py:

import pygame as pg
from collections import deque
from DrawEntity import DrawEntity

DrawEnt = deque()

def draw(window):
    d_Ent = DrawEntity()
    mouseX, mouseY = pg.mouse.get_pos()
    click = pg.mouse.get_pressed()
    if click[0]:
        rect = pg.draw.rect(window, (0, 0, 0), pg.Rect(mouseX, mouseY, 3, 3), 3)
        d_Ent.add(rect)

    if d_Ent.entity:
        print("new Entity")
        print(d_Ent)
        DrawEnt.append(d_Ent)



def main():

    running = True
    window = pg.display.set_mode((640, 480))
    window.fill((255, 255, 255))


    while running:
        clock.tick(3200)

        for event in pg.event.get():
            if event.type == pg.QUIT:
                running = False

            if event.type == pg.KEYDOWN:

                if event.key == pg.K_z and pg.key.get_mods() & pg.KMOD_LCTRL:

                    print(len(DrawEnt))

            draw(window)

        pg.display.flip()
    #end main loop
    pg.quit()

if __name__ == '__main__':

    pg.init()
    clock = pg.time.Clock()
    main()

还有 DrawEntity.py :

class DrawEntity:
def __init__(self):
    self.entity = []

def add(self, toAdd):
    self.entity.append(toAdd)

def remove(self):
    self.entity = []

def __str__(self):
    return ' '.join(map(str, self.entity))

基本上,我想进入一个 while 循环并留在那里,而我一直单击,以便将所有矩形收集到列表中,然后将其附加到主实体列表中,但是这不会进入 while 循环,并且每个当我绘制它时,它会为每个新实体附加一个矩形而不是一系列矩形。 (如果我尝试使用 while 循环游戏会崩溃)
所以:

-1 点击时收集我目前绘制的所有矩形

1.1 如果我停止单击,则将带有矩形列表的新 d_Ent 附加到主实体列表(main.py 中第 5 行的 DrawEnt)

  1. 继续程序
  2. 如果我再次单击,转到 1

【问题讨论】:

    标签: python graphics pygame draw


    【解决方案1】:

    每次单击鼠标按钮时,都必须创建一个新的DrawEntity 对象:

    if event.type == pg.MOUSEBUTTONDOWN and event.button == 1:
        DrawEnt.append(DrawEntity())
    

    在draw 中,您必须在deque (DrawEnt) 中的最后一个DrawEntity 上附加一个矩形:

    def draw(window):
        if len(DrawEnt) > 0:
            d_Ent = DrawEnt[-1]
    
            mouseX, mouseY = pg.mouse.get_pos()
            click = pg.mouse.get_pressed()
            if click[0]:
                rect = pg.draw.rect(window, (0, 0, 0), pg.Rect(mouseX, mouseY, 3, 3), 3)
                d_Ent.add(rect)
    

    在ctrl-z上删除DrawEnt(pop)的最后一个元素,清除显示并再次绘制所有剩余元素:

    if event.type == pg.KEYDOWN:
        if event.key == pg.K_z and pg.key.get_mods() & pg.KMOD_LCTRL:
            if len(DrawEnt) > 0:
                DrawEnt.pop()
                window.fill((255, 255, 255))
                for entity in DrawEnt:
                    for r in entity.entity:
                        pg.draw.rect(window, (0, 0, 0), r, 3)
    

    看例子:

    class DrawEntity:
        def __init__(self):
            self.entity = []
    
        def add(self, toAdd):
            self.entity.append(toAdd)
    
        def remove(self):
            self.entity = []
    
        def __str__(self):
            return ' '.join(map(str, self.entity))
    
    DrawEnt = deque()
    
    def draw(window):
        if len(DrawEnt) > 0:
            d_Ent = DrawEnt[-1]
    
            mouseX, mouseY = pg.mouse.get_pos()
            click = pg.mouse.get_pressed()
            if click[0]:
                rect = pg.draw.rect(window, (0, 0, 0), pg.Rect(mouseX, mouseY, 3, 3), 3)
                d_Ent.add(rect)
    
    def main():
    
        running = True
        window = pg.display.set_mode((640, 480))
        window.fill((255, 255, 255))
    
    
        while running:
            clock.tick(3200)
    
            for event in pg.event.get():
                if event.type == pg.QUIT:
                    running = False
    
                if event.type == pg.MOUSEBUTTONDOWN and event.button == 1:
                    d_Ent = DrawEntity()
                    DrawEnt.append(DrawEntity())
    
                if event.type == pg.KEYDOWN:
    
                    if event.key == pg.K_z and pg.key.get_mods() & pg.KMOD_LCTRL:
    
                        if len(DrawEnt) > 0:
                            DrawEnt.pop()
                            window.fill((255, 255, 255))
                            for entity in DrawEnt:
                                for r in entity.entity:
                                    pg.draw.rect(window, (0, 0, 0), r, 3)
    
                draw(window)
    
            pg.display.flip()
        #end main loop
        pg.quit()
    
    if __name__ == '__main__':
    
        pg.init()
        clock = pg.time.Clock()
        main()
    

    【讨论】:

    • 感谢您的评论,但是我需要平滑的绘图动作,我认为在您的解决方案中,我总是允许单击一次,因此它只会生成一个点而不是曲线(就像您在油漆上绘制时一样)
    • 我认为你没有运行我的代码,在我指定的代码中我已经有一个平滑的绘图。我的问题是关于如何为每次长按保存一个项目,想象你用鼠标画一条线而不从鼠标上移开手指,然后你按 ctrl_z 我希望它删除整行,而不仅仅是'最后一个像素创建'
    • @SendHelp 我改变了答案
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