感谢0A0D 的精彩回答。我很幸运。 Darin Dimitrov 也为限制 JS 文件的复杂性提出了很好的论据。不过,我确实发现在某些情况下,将函数折叠到它们的定义中会使浏览文件变得更加容易。
关于#region 一般而言,这个SO Question 很好地涵盖了它。
我对宏进行了一些修改以支持更高级的代码折叠。此方法允许您在 //#region 关键字 ala C# 之后放置描述,并在代码中显示如下:
示例代码:
//#region InputHandler
var InputHandler = {
inputMode: 'simple', //simple or advanced
//#region filterKeys
filterKeys: function(e) {
var doSomething = true;
if (doSomething) {
alert('something');
}
},
//#endregion filterKeys
//#region handleInput
handleInput: function(input, specialKeys) {
//blah blah blah
}
//#endregion handleInput
};
//#endregion InputHandler
更新宏:
Option Explicit On
Option Strict On
Imports System
Imports EnvDTE
Imports EnvDTE80
Imports EnvDTE90
Imports System.Diagnostics
Imports System.Collections.Generic
Public Module JsMacros
Sub OutlineRegions()
Dim selection As EnvDTE.TextSelection = CType(DTE.ActiveDocument.Selection, EnvDTE.TextSelection)
Const REGION_START As String = "//#region"
Const REGION_END As String = "//#endregion"
selection.SelectAll()
Dim text As String = selection.Text
selection.StartOfDocument(True)
Dim startIndex As Integer
Dim endIndex As Integer
Dim lastIndex As Integer = 0
Dim startRegions As New Stack(Of Integer)
Do
startIndex = text.IndexOf(REGION_START, lastIndex)
endIndex = text.IndexOf(REGION_END, lastIndex)
If startIndex = -1 AndAlso endIndex = -1 Then
Exit Do
End If
If startIndex <> -1 AndAlso startIndex < endIndex Then
startRegions.Push(startIndex)
lastIndex = startIndex + 1
Else
' Outline region ...
Dim tempStartIndex As Integer = CInt(startRegions.Pop())
selection.MoveToLineAndOffset(CalcLineNumber(text, tempStartIndex), CalcLineOffset(text, tempStartIndex))
selection.MoveToLineAndOffset(CalcLineNumber(text, endIndex) + 1, 1, True)
selection.OutlineSection()
lastIndex = endIndex + 1
End If
Loop
selection.StartOfDocument()
End Sub
Private Function CalcLineNumber(ByVal text As String, ByVal index As Integer) As Integer
Dim lineNumber As Integer = 1
Dim i As Integer = 0
While i < index
If text.Chars(i) = vbLf Then
lineNumber += 1
i += 1
End If
If text.Chars(i) = vbCr Then
lineNumber += 1
i += 1
If text.Chars(i) = vbLf Then
i += 1 'Swallow the next vbLf
End If
End If
i += 1
End While
Return lineNumber
End Function
Private Function CalcLineOffset(ByVal text As String, ByVal index As Integer) As Integer
Dim offset As Integer = 1
Dim i As Integer = index - 1
'Count backwards from //#region to the previous line counting the white spaces
Dim whiteSpaces = 1
While i >= 0
Dim chr As Char = text.Chars(i)
If chr = vbCr Or chr = vbLf Then
whiteSpaces = offset
Exit While
End If
i -= 1
offset += 1
End While
'Count forwards from //#region to the end of the region line
i = index
offset = 0
Do
Dim chr As Char = text.Chars(i)
If chr = vbCr Or chr = vbLf Then
Return whiteSpaces + offset
End If
offset += 1
i += 1
Loop
Return whiteSpaces
End Function
End Module