用于 OSM PointOfInterest 的 Neo4j 中的路由

Question

1.我已经下载了一个城市的OSM文件，并通过https://github.com/neo4j-contrib/osm将数据导入Neo4j

2.Followed README，我添加了距离、交点、ROUTE 关系、PointOfInterest。

3.但是ROUTE关系是双向的，不知道这是否是导致路由算法失败的原因。

仅供参考，我的上述步骤脚本

1. 计算距离

'MATCH
(awn:OSMWayNode)-[r:NEXT]-(bwn:OSMWayNode)
WHERE NOT exists(r.distance)
RETURN awn,bwn,r',
'MATCH
(awn)-[:NODE]->(a:OSMNode),
(bwn)-[:NODE]->(b:OSMNode)
SET r.distance=round(distance(a.location,b.location))',
{batchSize:10000,parallel:false});

2.判断什么是交集

'MATCH(n:OSMNode)
WHERE size((n)<-[:NODE]-())>2
AND NOT (n:Intersection)
RETURN n',
'MATCH
(n)<-[:NODE]-(wn:OSMWayNode),(wn)<-[:NEXT*]-(wx),
(wx)<-[:FIRST_NODE]-(w:OSMWay)-[:TAGS]->(wt:OSMTags)
WHERE exists(wt.highway)

SET n:Intersection',
{batchSize:10000,parallel:false});

3.用新的距离关系连接决策点（交叉点）

'MATCH(x:Intersection)
CALL spatial.osm.routeIntersection(x,false,false,false)
YIELD fromNode,toNode,distance,fromRel,toRel
RETURN fromNode,toNode,distance,fromRel,toRel',
'MERGE (fromNode)-[r:ROUTE {fromRel:id(fromRel),toRel:id(toRel)}]->(toNode)
ON CREATE SET r.distance=round(distance)',
{batchSize:10000,parallel:false});

4.创建兴趣点，按照我为位置创建另外3个兴趣点的相同方式：{longitude:103.835553,latitude:1.3045739},{longitude:103.78152251,latitude:1.28357103},{longitude:103.8604644,latitude: 1.305788741}

MATCH(n:OSMNode)
WHERE
distance(n.location,point({longitude:103.8958005,latitude:1.330945169})
)<100 AND (n)-[:ROUTE]->() and NOT n:PointOfInterest
WITH n,n.location as poi LIMIT 1
MATCH(m:OSMNode)
WHERE distance(poi,m.location)<100
WITH n,m
MATCH(m)<-[:NODE]-(wn:OSMWayNode),
(wn)<-[:NEXT*]-(wx),
(wx)<-[:FIRST_NODE]-(w:OSMWay)
WITH n,w
WITH n,COLLECT(w) AS ways
CALL spatial.osm.routePointOfInterest(n,ways) YIELD node
SET n:PointOfInterest,n.name="AAA"
RETURN count(node)

问题：

我想使用 gds.alpha.spanningTree.minimum.write 来获得从 AAA 点到所有其他 PointOfInterest 的最小努力，即 BBB、CCC、DDD

CALL gds.alpha.spanningTree.minimum.write({
  nodeProjection: 'PointOfInterest',
  relationshipProjection: {
    ROUTE: {
      type: 'ROUTE',
      properties: 'distance',
      orientation: 'UNDIRECTED'
    },
    startNodeId: id(n),
    relationshipWeightProperty: 'distance',
    writeProperty: 'MINST',
    weightWriteProperty: 'writeCost'
  }
})
YIELD createMillis, computeMillis, writeMillis, effectiveNodeCount
RETURN createMillis, computeMillis, writeMillis, effectiveNodeCount;

但我总是出错

Failed to invoke procedure `gds.alpha.spanningTree.minimum.write`: Caused by: java.lang.IllegalArgumentException: Cannot construct a relationship filter out of a java.lang.Long

是否可以使用上述方式实现我的目的？如果可以，我的密码有什么问题吗？

Answer 1

关于您的错误，很遗憾，documented examples 中的一些错误是错误的。看起来您正在尝试遵循其中一个错误的示例。

relationshipProjection 应该只包含ROUTE，而不能包含其他属性。

试试这个：

CALL gds.alpha.spanningTree.minimum.write({
  nodeProjection: 'PointOfInterest',
  relationshipProjection: {
    ROUTE: {
      type: 'ROUTE',
      properties: 'distance',
      orientation: 'UNDIRECTED'
    }
  },
  startNodeId: id(n),
  relationshipWeightProperty: 'distance',
  writeProperty: 'MINST',
  weightWriteProperty: 'writeCost'
})
YIELD createMillis, computeMillis, writeMillis, effectiveNodeCount
RETURN createMillis, computeMillis, writeMillis, effectiveNodeCount;

我为文档问题创建了一个issue。