Vimeo 获取请求 405 响应代码错误答案

【问题标题】：Vimeo Get request 405 response code errorVimeo 获取请求 405 响应代码错误
【发布时间】：2016-07-26 06:49:59
【问题描述】：

https://player.vimeo.com/video/136004191/config 尝试从 vimeo 获取真实 URL，而我遇到错误：

response code:405
07-26 11:42:46.236 22054-22183/com.sample.samplevideoview W/System.err: java.io.FileNotFoundException: https://player.vimeo.com/video/136004191/config
07-26 11:42:46.236 22054-22183/com.sample.samplevideoview W/System.err:     at com.android.okhttp.internal.huc.HttpURLConnectionImpl.getInputStream(HttpURLConnectionImpl.java:238)
07-26 11:42:46.236 22054-22183/com.sample.samplevideoview W/System.err:     at com.android.okhttp.internal.huc.DelegatingHttpsURLConnection.getInputStream(DelegatingHttpsURLConnection.java:210)
07-26 11:42:46.236 22054-22183/com.sample.samplevideoview W/System.err:     at com.android.okhttp.internal.huc.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at com.sample.samplevideoview.AsyncHttpClient$AsyncDataRequestHideDialog.doInBackground(AsyncHttpClient.java:353)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at com.sample.samplevideoview.AsyncHttpClient$AsyncDataRequestHideDialog.doInBackground(AsyncHttpClient.java:287)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at android.os.AsyncTask$2.call(AsyncTask.java:295)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at java.util.concurrent.FutureTask.run(FutureTask.java:237)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
07-26 11:42:46.237 22054-22183/com.sample.samplevideoview W/System.err:     at java.lang.Thread.run(Thread.java:818)
07-26 11:42:46.281 22054-22054/com.sample.samplevideoview E/MainActivity: Must implement the interface java.lang.NullPointerException: Attempt to invoke virtual method 'com.sample.samplevideoview.Request com.sample.samplevideoview.VimeoResponse.getRequest()' on a null object reference

代码如下：

    private void getRealUrl(String videoId)
        {
            AsyncHttpClient mAsyncHttpClient = new AsyncHttpClient();
            HashMap<String, String> params = new HashMap<>();
            String url = "https://player.vimeo.com/video/" + videoId + "/config";

            mAsyncHttpClient.postWithStringData(MainActivity.this, TAG,
                    url, StringConstants.METHOD_GET, params,false,
                    new AsyncHttpClient.AsyncHttpResponseCallBack() {
                        @Override
                        public void onResponse(String response) {
                            Gson gson = new GsonBuilder().create();
                            VimeoResponse movie = gson.fromJson(response, VimeoResponse.class);

                        }
                    }
        );
        }
public class AsyncHttpClient {

    public interface AsyncHttpResponseCallBack {
        void onResponse(String response);
    }

    private Vector<Object> params;
    private static final String UTF_ENCODING = "UTF-8";

    private static final int CONTEXT_INDEX = 0;
    private static final int TAG_INDEX = 1;
    private static final int URL_INDEX = 2;
    private static final int PARAMS_STRING_INDEX = 3;
    private static final int RESPONSE_CALLBACK_INDEX = 4;
    private static final int REQUEST_METHOD_INDEX = 5;
    private static final int SHOW_PROGRESS_DIALOG_INDEX = 6;
public void postWithStringData(Context context, String TAG, String url, String method,
                                   HashMap<String, String> hashMapParams, boolean showDialog,
                                   AsyncHttpResponseCallBack asyncHttpResponseCallBack) {
        if (Utilities.isConnected(context)) {
            try {
                params = new Vector<>();
                params.insertElementAt(context, CONTEXT_INDEX);
                params.insertElementAt(TAG, TAG_INDEX);
                params.insertElementAt(url, URL_INDEX);
                params.insertElementAt(getPostDataString(hashMapParams), PARAMS_STRING_INDEX);
                params.insertElementAt(asyncHttpResponseCallBack, RESPONSE_CALLBACK_INDEX);
                params.insertElementAt(method, REQUEST_METHOD_INDEX);
                new AsyncDataRequestHideDialog(context).execute(params);
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            }
        }
    }
private class AsyncDataRequestHideDialog extends AsyncTask<Vector<Object>, Void, String> {

        AlertDialog mAlert;
        String TAG, url;
        String paramsString;
        AsyncHttpResponseCallBack asyncHttpResponseCallBack;
        Context context;

        String method;
        public AsyncDataRequestHideDialog(Context context) {
            // TODO Auto-generated constructor stub
            this.context = context;
        }

        @Override
        protected String doInBackground(Vector<Object>... params) {
            Vector<Object> requestParams = params[0];
            TAG = (String) requestParams.get(TAG_INDEX);
            url = (String) requestParams.get(URL_INDEX);
            paramsString = (String) requestParams.get(PARAMS_STRING_INDEX);
            asyncHttpResponseCallBack = (AsyncHttpResponseCallBack) requestParams.get(RESPONSE_CALLBACK_INDEX);
            method = (String) requestParams.get(REQUEST_METHOD_INDEX);

            String result = "";
            URL requestURL;
            StringBuffer response;

            try {
                requestURL = new URL(url);
                HttpURLConnection conn = (HttpURLConnection) requestURL.openConnection();
                conn.setReadTimeout(StringConstants.READ_TIMEOUT);
                conn.setConnectTimeout(StringConstants.CONNECTION_TIMEOUT);
                conn.setRequestMethod(method);
                conn.setDoInput(true);
                conn.setDoOutput(true);
                OutputStream os = conn.getOutputStream();
                BufferedWriter writer = new BufferedWriter(
                        new OutputStreamWriter(os, UTF_ENCODING));
                writer.write(paramsString);
                writer.flush();
                writer.close();
                os.close();
                String line;
                response = new StringBuffer();
                Log.d(TAG,"response code:"+conn.getResponseCode());
                BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));
                while ((line = br.readLine()) != null) {
                    response.append(line);
                }
                result = response.toString();
            } catch (SocketTimeoutException e1) {
                e1.printStackTrace();
            } catch (Exception e) {
                e.printStackTrace();

            } finally {
                Log.d(TAG, result);
                return result;
            }
        }

        // Overriding onPreExecute to initialize and show progress dialog
        @Override
        protected void onPreExecute() {
            // TODO Auto-generated method stub
            super.onPreExecute();

        }
        @Override
        protected void onPostExecute(String result) {
            // TODO Auto-generated method stub
            super.onPostExecute(result);

            // If result is not null
            if (result != null) {
                try {
                    // Making a log just to make sure of data.
                    Log.e(TAG, result);
                    asyncHttpResponseCallBack.onResponse(result);
                } catch (Exception e) {
                    Log.e(TAG, "Must implement the interface " + e.toString());
                }
            } else {
                mAlert = Utilities.createAlertDialog(context, "Error",
                        StringConstants.DATA_ERROR);
            }
        }
    }

当我收到响应代码 405 时？什么问题？移动和桌面浏览器中的相同 url 响应我。

【问题讨论】：

确保 URL 接受的方法是 GET 或 PUSH
@GeetChoubey 请解释一下
从哪里可以找到它的 GET 或 PUSH ？
尝试 Postman 或 AdvanceDREST Client chrome 扩展来测试 URL。在此处添加您正在使用的标头并测试 POST 和 GET 方法的 URL。
我已经用 GET 请求在邮递员上测试了 url，它工作正常，邮递员 @GeetChoubey 不需要标头

标签： android vimeo vimeo-player vimeo-android

【解决方案1】：

我强烈建议使用官方的vimeo-networking Java/Android 库来与 Vimeo API 对话。

该库将处理所有网络逻辑（因此您不需要 HttpURLConnection 样板），它还提供通过 URI 获取视频的调用。

Here is how to request a single video。它基本上看起来像：

String uri = ...;// the video uri; if you have a Video, this is video.uri
VimeoClient.getInstance().fetchNetworkContent(uri, new ModelCallback<Video>(Video.class) {
     @Override
     public void success(Video video) {
          // use the video
     }

     @Override
     public void failure(VimeoError error) {
          // voice the error
     }
});

然后，如果您拥有该视频，则可以直接从库中的 Video 对象访问您想要的任何信息。像video.files 这样的信息会返回一个VideoFile，让您可以访问您想要的链接。

【讨论】：

如果您拥有该视频，您可以访问任何信息，我没有我自己的 vimeo 帐户，也没有我自己设置的任何视频。此外，我只有视频链接，即 youtube、dailymotion、 vimeo 所以我只需要使用它自己的 sdk 播放 vimeo 视频，因为我没有从我的 api 响应中获取真正的 url
使用 API，如果您是上传该视频的人（使用 PRO 帐户），您只能访问 Video 上的 files 对象。在网络上，有一个“嵌入式播放器”可以让你播放任何视频，但到目前为止，Android 上还没有嵌入式播放器选项。请参阅this link，其中介绍了使用WebView 在Android 上获取播放器来播放网络嵌入式播放器。

【解决方案2】：

您的代码似乎有问题，因为对于简单的 GET 字符串请求 OutputStream 和 Buffer 类导致异常。试试这个简单的代码。在我这边工作得很好。

 @Override
            protected String doInBackground(Vector<Object>... params) {

                String result = "";
                url = "https://player.vimeo.com/video/136004191/config";

                try {

                    URL obj = new URL(url);

                    HttpURLConnection con = (HttpURLConnection) obj.openConnection();

                    // optional default is GET
                    con.setRequestMethod("GET");
                    BufferedReader in = new BufferedReader(
                            new InputStreamReader(con.getInputStream()));
                    String inputLine;
                    StringBuffer response = new StringBuffer();

                    while ((inputLine = in.readLine()) != null) {
                        response.append(inputLine);
                    }
                    in.close();

                    //print result
                    System.out.println(response.toString());

                    result = response.toString();
                } catch (SocketTimeoutException e1) {
                    e1.printStackTrace();
                } catch (Exception e) {
                    e.printStackTrace();

                } finally {
                    Log.d(TAG, result);
                    return result;
                }
            }

【讨论】：