【发布时间】:2016-11-05 13:45:03
【问题描述】:
伙计们,我正在研究音频可视化,并在 pde 中制作了一个成功的运行文件。该代码采用“input.mp3”,然后导出 .mp4 文件。我们可以通过终端(.sh)使用它吗?我的意思是通过编写一些命令来执行程序。喜欢:
processing-3.2.2 filename.pde input.mp3
它会生成该 input.mp3 的视频。这是我的代码:
import ddf.minim.*;
import ddf.minim.analysis.*;
import com.hamoid.*;
Minim minim;
AudioPlayer player;
AudioMetaData meta;
BeatDetect beat;
VideoExport videoExport;
int r = 200;
float rad = 70;
void setup()
{
size(600, 600);
//size(600, 400);
minim = new Minim(this);
player = minim.loadFile("son_final.mp3");
meta = player.getMetaData();
beat = new BeatDetect();
videoExport = new VideoExport(this, "basic.mp4");
player.loop();
//player.play();
background(-1);
noCursor();
}
void draw()
{
float t = map(mouseX, 0, width, 0, 1);
beat.detect(player.mix);
fill(#1A1F18, 20);
noStroke();
rect(0, 0, width, height);
translate(width/2, height/2);
noFill();
fill(-1, 10);
if (beat.isOnset()) rad = rad*0.9;
else rad = 70;
ellipse(0, 0, 2*rad, 2*rad);
stroke(-1, 50);
int bsize = player.bufferSize();
for (int i = 0; i < bsize - 1; i+=5)
{
float x = (r)*cos(i*2*PI/bsize);
float y = (r)*sin(i*2*PI/bsize);
float x2 = (r + player.left.get(i)*100)*cos(i*2*PI/bsize);
float y2 = (r + player.left.get(i)*100)*sin(i*2*PI/bsize);
line(x, y, x2, y2);
}
beginShape();
noFill();
stroke(-1, 50);
for (int i = 0; i < bsize; i+=30)
{
float x2 = (r + player.left.get(i)*100)*cos(i*2*PI/bsize);
float y2 = (r + player.left.get(i)*100)*sin(i*2*PI/bsize);
vertex(x2, y2);
pushStyle();
stroke(-1);
strokeWeight(2);
point(x2, y2);
popStyle();
}
endShape();
if (flag) showMeta();
videoExport.saveFrame();
}
void showMeta() {
int time = meta.length();
textSize(50);
textAlign(CENTER);
text( (int)(time/1000-millis()/1000)/60 + ":"+ (time/1000-millis()/1000)%60, -7, 21);
}
boolean flag =false;
void mousePressed() {
if (dist(mouseX, mouseY, width/2, height/2)<150) flag =!flag;
}
void keyPressed() {
if(key==' ')exit();
if(key=='s')saveFrame("###.jpeg");
}
【问题讨论】:
标签: shell audio video terminal processing