在 android 中使用 List<NameValuePair> 创建一个 json 字符串

Question

我想用 Android 向一个 url 发送一个 http 请求。 我是一名 iOS 开发人员，现在正在尝试学习 Android。 我曾经在 iOS 中发送JSON 字符串，如下所示

 {"function":"login", "parameters": {"username": "nithin""password": "123456"}}

如何在 Android 中发送此内容？ 我试过List<NameValuePair>，但找不到合适的解决方案。

我尝试过的完整代码 -

    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(URL);

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("function", "login"));
        nameValuePairs.add(new BasicNameValuePair("username", "nithin"));
        nameValuePairs.add(new BasicNameValuePair("password", "123456"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(httppost);

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }

Answer 1

我认为 JsonStringer 在这里对您来说既简单又有用..

试试这个：

   HttpPost request = new HttpPost(URL);
   request.setHeader("Accept", "application/json");
   request.setHeader("Content-type", "application/json");
   JSONStringer vm;
   try {
         vm = new JSONStringer().object().key("function")
        .value(login).key("parameters").object()
        .key("username")
        .value(nithin).key("password").value("123456")
        .endObject().endObject();
  StringEntity entity = new StringEntity(vm.toString());
  request.setEntity(entity);
  HttpClient httpClient = new DefaultHttpClient();
  HttpResponse response = httpClient.execute(request);