【发布时间】：2016-03-14 07:37:31
【问题描述】：
我正在尝试使用 Android Studio 在列表视图中显示 JSON 响应。但是，我不知道如何处理重复的 JSON 响应。
这是我的 JSON 响应：
{"回复": [{"dfirst_name":"Kelvin","dlast_name":"Cheung","medicine":"氨氯地平","start_date":"2016-03-02","end_date": "2016-03-06","dosage":"50mg","instructions":"每天 4 次"},{"dfirst_name":"Simon","dlast_name":"Yam","medicine":"氨氯地平","start_date":"2016-05-09","end_date":"2016-05-19","dosage":"100mg","instructions":"每天2次，额外剂量"},
这是我的 android studio 项目中 showJSON() 的 sn-p。
private void showJSON(字符串响应){
String first_name="";
String last_name="";
String nationality="";
String hkid="";
String dob="";
String age="";
String gender="";
String bloodtype="";
String emergency_contact="";
String relationship="";
String mobile="";
String food_algy="";
String drug_algy="";
String dfirst_name="";
String dlast_name="";
String medicine="";
String start_date="";
String end_date="";
String dosage="";
String instructions="";
String in_date="";
String out_date="";
try {
JSONObject jsonObject = new JSONObject(response);
JSONArray result = jsonObject.getJSONArray("response");
JSONObject c = result.getJSONObject(0);
first_name = c.getString(Config.KEY_FIRST_NAME);
last_name = c.getString(Config.KEY_LAST_NAME);
nationality = c.getString(Config.KEY_NATIONALITY);
hkid = c.getString(Config.KEY_HKID);
dob = c.getString(Config.KEY_DOB);
age = c.getString(Config.KEY_AGE);
gender = c.getString(Config.KEY_GENDER);
bloodtype = c.getString(Config.KEY_BLOODTYPE);
emergency_contact = c.getString(Config.KEY_EMERGENCYCONTACT);
relationship = c.getString(Config.KEY_RELATIONSHIP);
mobile = c.getString(Config.KEY_MOBILE);
in_date = c.getString(Config.KEY_IN_DATE);
out_date = c.getString(Config.KEY_OUT_DATE);
food_algy = c.getString(Config.KEY_FOOD_ALGY);
drug_algy = c.getString(Config.KEY_DRUG_ALGY);
dfirst_name = c.getString(Config.KEY_DFIRST_NAME);
dlast_name = c.getString(Config.KEY_DLAST_NAME);
medicine = c.getString(Config.KEY_MEDICINE);
start_date = c.getString(Config.KEY_START_DATE);
end_date = c.getString(Config.KEY_END_DATE);
dosage = c.getString(Config.KEY_DOSAGE);
instructions = c.getString(Config.KEY_INSTRUCTIONS);
} catch (JSONException e) {
e.printStackTrace();
}
textViewResult.setMovementMethod(new ScrollingMovementMethod());
textViewResult.setText(Html.fromHtml("<font size=4><b>General Information: </b></font><br> " +
"<font size=4>Name: </font>" + first_name + " "+ last_name + "<br>"+
"<font size=4>Nationality: </font>" + nationality + "<br>"+
"<font size=4>HKID: </font>" + hkid + "<br>"+
"<font size=4>Date of Birth: </font>" + dob + "<br>"+
"<font size=4>Age: </font>" + age + "<br>"+
"<font size=4>Gender: </font>" + gender + "<br>"+
"<font size=4>Blood Type: </font>" + bloodtype + "<br><br>" +
"<font size=2><b>Allergies: </b></font><br>" +
"<font size=4>Food Allergy: </font>" + food_algy +"<br>"+
"<font size=4>Drug Allergy: </font>" + drug_algy +"<br><br>"+
"<font size=2><b>Admission History: </b></font><br>" +
"<font size=4>Admitted on: </font>" + in_date +"<br>"+
"<font size=4 >Discharged on: </font>" + out_date +"<br><br>"+
"<font size=2><b>Emergency Contact: </b></font><br>" +
"<font size=4>Contact Person: </font>" + emergency_contact +"<br>"+
"<font size=4>Relationship: </font>" + relationship + "<br>"+
"<font size=4>Mobile: </font>" + mobile));
}
到目前为止，我可以在“textViewResult.setText()”中按预期输出所有其他信息，因为这些信息的 JSON 响应是非重复的。
谁能帮助并告诉我如何遍历重复的 JSON 响应并以与其他信息类似的格式输出它。
【问题讨论】：
-
您想遍历 JSON 响应中的每个人吗？这就是你所说的重复吗？
标签： javascript android html json