org.json.JSONException: org.json.JSONArray 类型的 Value [] 无法在 Android 中转换为 JSONObject

Question

我收到了这个错误：

org.json.JSONException: org.json.JSONArray 类型的值 [] 无法转换为 JSONObject

我正在尝试根据过滤器显示来自 android 应用程序内部数据库的一些记录。邮递员向我显示正确的结果显示错误。我在第二个应用程序中使用了基本相同的方法并且它有效。

PHP 脚本：

function findUsers($odkial, $co){
        $stmt = $this->con->prepare("SELECT Meno, RodneCislo, PIK FROM zamestnanci WHERE $odkial LIKE ?");
        $stmt->bind_param("s", $co);
        $stmt->execute();
        $stmt->bind_result($Meno, $RC, $PIK);

        $foundUsers = array(); 

        while($stmt->fetch()){
        $user  = array();
        $user['meno'] = $Meno;
        $user['rodnecislo'] = $RC; 
        $user['pik'] = $PIK; 

        array_push($foundUsers, $user); 
        }

        return $foundUsers; 
        }

从编辑文本和微调器中获取一些参数的Android代码方法：

public void hladajZaznamy(){
    HashMap<String, String> params = new HashMap<>();
    String pod = podla.getSelectedItem().toString();
    String co = "%"+podlac.getText().toString()+"%";
    params.put("PodlaCoho", pod);
    params.put("Co", co);

    PerformNetworkRequest request = new PerformNetworkRequest(Api.HLADAJ_ZAMESTNANCA, params, CODE_POST_REQUEST);
    request.execute();

}

Android 代码网络请求：

 private class PerformNetworkRequest extends AsyncTask<Void, Void, String> {

    String url;

    HashMap<String, String> params;

    int requestCode;

    PerformNetworkRequest(String url, HashMap<String, String> params, int requestCode) {
        this.url = url;
        this.params = params;
        this.requestCode = requestCode;
    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }


    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute(s);
        try {
            JSONObject object = new JSONObject(s); // HERE IS THE ERROR
            if (!object.getBoolean("error")) {
                Toast.makeText(getApplicationContext(), object.getString("message"), Toast.LENGTH_SHORT).show();
                saveRecords(object.getJSONArray("foundUsers"));
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

    //the network operation will be performed in background
    @Override
    protected String doInBackground(Void... voids) {
        RequestHandler requestHandler = new RequestHandler();

        if (requestCode == CODE_POST_REQUEST)
            return requestHandler.sendPostRequest(url, params);


        if (requestCode == CODE_GET_REQUEST)
            return requestHandler.sendGetRequest(url);

        return null;
    }
}

还有一些邮递员的结果，例如 PodlaCoho = Meno 和 Co = %TESTTEST% 时：

{"error":false,"message":"Zamestnanci uspesne vyhladani","foundUsers":[{"meno":"TESTTEST","rodnecislo":"1111225555","pik":"111111"}]}

感谢您的建议:)

Answer 1

这是因为您要转换为JSONObject 的响应字符串应该是JSONArray 的形式，所以将出错的行改成这个。

@Override
protected void onPostExecute(String s) {
    super.onPostExecute(s);
    JSONArray objectArray = new JSONArray();
    for (int i = 0; i < objectArray.length(); i++) {
        //here you can iterate through the array elements and find respective JSONObject and/or other values.
    }
}

希望这会有所帮助..