如何在 TextView 中获取 JSON 值？答案

【问题标题】：How can I get the JSON values in the TextView?如何在 TextView 中获取 JSON 值？
【发布时间】：2019-11-25 07:00:12
【问题描述】：

这是我用来设置文本的布局：Image Here, please Click

这是我正在使用的数组列表：

 myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_google_classroom, "Classroom","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_news_alerts, "Notice","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_school_rank, "Announcement","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.school_diary, "School Diary","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_absent_report, "Absent report","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.examination, "Examination","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_events, "Events","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.edu_forum_finals, "Edu Forum","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_resources, "Edu Bank","sds"));
        myTeacherModelLists.add(new MyTeacherModel(R.drawable.home_help, "Help","sds"));

这是我的 JSON 响应：

{
        "Badges": {
            "Notice": 0,
            "Event": 0
        },
        "Response": {
            "ResponseVal": 1,
            "Reason": "Success! Record Found."
        }
    }

这是 StringRequest 代码，我使用的是 Volley：

 StringRequest stringRequest = new StringRequest(Request.Method.GET, URL, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.e("URL : ", URL);

            try {
                JSONObject jsonObject = new JSONObject("Badges");
                Log.e("Response is : ", String.valueOf(jsonObject));
            } catch (JSONException e) {
                e.printStackTrace();
            }


        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

        }
    });

    RequestQueue requestQueue = Volley.newRequestQueue(this);
    requestQueue.add(stringRequest);

这是我的模型类：

public class MyTeacherModel {

Integer images;
String text;
String Badges;

public MyTeacherModel(){

}

public MyTeacherModel(Integer images, String text, String badges) {
    this.images = images;
    this.text = text;
    Badges = badges;
}

public Integer getImages() {
    return images;
}

public String getText() {
    return text;
}

public String getBadges() {
    return Badges;
}

目前我使用的是硬编码文本，如何从这个 JSON 中获取数据到 TextViews？

【问题讨论】：

你想知道如何解析JSON吗？
我只想知道如何从 json 响应中获取值并将其设置在 TextView 中？
你需要解析JSON
您可以（实际上必须）先使用搜索。
How to parse json parsing Using GSON in android的可能重复

标签： android json

【解决方案1】：

请试试这个代码

StringRequest stringRequest = new StringRequest(Request.Method.GET, URL, new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {

        try {
            JSONObject jsonObject = new JSONObject(response);

            JSONObject jsonObjectBadges = jsonObject.getJSONObject("Badges");
            int Notice = jsonObjectBadges.getInt("Notice");
            int Event = jsonObjectBadges.getInt("Event");

            JSONObject jsonObjectResponse = jsonObject.getJSONObject("Response");
            int ResponseVal = jsonObjectResponse.getInt("ResponseVal");
            String Reason = jsonObjectResponse.getString("Reason");

            Log.e("URL_DATA : ", "Notice : " + Notice  + "\n" + 
            "Event : " + Event  + "\n" + 
            "ResponseVal : " + ResponseVal  + "\n" +
            "Reason : " + Reason  + "\n");

        } catch (JSONException e) {
            e.printStackTrace();
        }


    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {

    }
});

RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);

【讨论】：

【解决方案2】：

您需要使用 java json 对象将 json 文本序列化和反序列化为 java 模型。为了获得更好的体验，请使用 Gson 、 Moshi 、 Jackson 等库

try {
            JSONObject jsonObject = new JSONObject("Badges");
            Log.e("Response is : ", String.valueOf(jsonObject));
        } catch (JSONException e) {
            e.printStackTrace();
        }

试试这个：

try {
            JSONObject jsonObject = new JSONObject(response);
            Log.e("Response is : ", String.valueOf(jsonObject));
        } catch (JSONException e) {
            e.printStackTrace();
        }

该响应是您的 json 字符串并且可以初始化。

【讨论】：

【解决方案3】：

您需要通过以下方式根据您的 json 响应创建模型类：

如果您的 JSON 响应：

{
    "Badges": {
         "Notice": 0,
         "Event": 0
     },
    "Response": {
         "ResponseVal": 1,
         "Reason": "Success! Record Found."
     }
}

那么你的模型类应该是（你需要创建三个模型类）：

class NetworkResponse {
   Badges Badges;  // Note: name of your variable should be same as the field received in 
                   // JSON response
   Response Response;
}

class Badges {
  int Notice;
  int Event;
}

class Response {
  int ResponseVal;
  String Reason;
}

现在在 volley 生成的字符串请求代码中，您需要使用 GSON 库按以下方式解析 JSON 响应。

StringRequest stringRequest = new StringRequest(Request.Method.GET, URL, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.e("URL : ", URL);

            try {
                Gson gson = new Gson();
                NetworkResponse responseObject = gson.fromJson(response,NetworkResponse.class)

            } catch (JSONException e) {
                e.printStackTrace();
            }


        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

        }
    });

    RequestQueue requestQueue = Volley.newRequestQueue(this);
    requestQueue.add(stringRequest);

您可以从 responseObject 访问您的值并通过以下方式将它们填充到您的文本视图中：

textView.setText(responseObject.Badges.Notice)
textView.setText(responseObject.Badges.Event)

textView.setText(responseObject.Response.ResponseVal)
textView.setText(responseObject.Response.Reason)

【讨论】：