java - 如何区分数组的值与Java中具有相同键的两个对象

Question

我正在实现一个 Android 应用。我有一个 100 行 2 列的谷歌电子表格。我正在我的应用程序中获取谷歌电子表格的记录。我得到了这样的 JSON 响应：

JSON Response

{
     "version": "0.6",
      "reqId": "0",
      "status": "ok",
      "sig": "862971983",
      "table": {
        "cols": [
          {
            "id": "A",
            "label": "Name",
            "type": "string"
          },
          {
            "id": "B",
            "label": "PhoneNo",
            "type": "number",
            "pattern": "General"
          }
        ],
        "rows": [
          {
            "c": [
              {
                "v": "A Anil C Agrawal"
              },
              {
                "v": 7926605853,
                "f": "7926605853"
              }
            ]
          },
          {
            "c": [
              {
                "v": "A Balaji Agarwal"
              },
              {
                "v": 8463225752,
                "f": "8463225752"
              }
            ]
          },.................

这里我有 C 是数组类型，其中两个对象具有相同的键，但我希望在 Ex 的不同变量中使用相同的键。字符串名称，字符串电话号码。

这是我获取谷歌电子表格响应并打印它的方法。如果我打印 Name 的值，那么它会同时显示 Name 和电话号码，但我想要 Name= Abc 和 PhoneNo = 8574968521。

public void getSpreadSheetData() {
        String result = getSpreadSheetResponce();
        List<String> arrayList = new ArrayList<String>();
        if (result == null) {
            Log.e("net not present:", "");
        } else {
            int start = result.indexOf("{", result.indexOf("{") + 1);
            int end = result.lastIndexOf("}");
            String jsonResponse = result.substring(start, end);

            try {
                JSONObject mainObj = new JSONObject(jsonResponse);
                String Name = null;

                if (mainObj != null) {
                    JSONArray list = mainObj.getJSONArray("rows");
                    if (list != null) {
                        for (int i = 0; i < list.length(); i++) {
                            JSONObject innerJsonObject = list.getJSONObject(i);
                            if (innerJsonObject != null) {
                                //
                                JSONArray valuesJsonArray = innerJsonObject
                                        .getJSONArray("c");
                                if (valuesJsonArray != null) {
                                    for (int j = 0; j < valuesJsonArray
                                            .length(); j++) {
                                        JSONObject innerElem = valuesJsonArray
                                                .getJSONObject(j);
                                        if (innerElem != null) {
                                            Name = innerElem.getString("v");
                                            arrayList.add(Name);
                                            Log.i("arrayList", "" + arrayList);

                                        }
                                    }
                                }
                            }
                        }
                    }
                }
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }

    }

    private String getSpreadSheetResponce() {

        String responce = " ";
        String urlString = "";
        try {
            String FETCH_ROW_WITH_WHERE_CLAUSE_URL = "https://spreadsheets.google.com/tq?tq&key=1n_VjwHm8qIU5YRMM-wMkJIap2KZa5vOfxWI5dpYT1PE&gid=1262286779";
            URL urlspreadsheet = new URL(FETCH_ROW_WITH_WHERE_CLAUSE_URL);
            URLConnection urlConnection = urlspreadsheet.openConnection();
            HttpURLConnection connection = null;
            if (urlConnection instanceof HttpURLConnection) {
                connection = (HttpURLConnection) urlConnection;
            } else {
                System.out.println("Please enter an HTTP URL.");
            }
            BufferedReader in = new BufferedReader(new InputStreamReader(
                    connection.getInputStream()));
            String current;

            while ((responce = in.readLine()) != null) {
                urlString += responce;
                System.out.println(urlString);
                Log.e("Response::", "in loop:" + urlString);
            }
            Log.e("Response::", "final response:" + urlString);
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return urlString;

    }  

有可能吗，请帮帮我。

Answer 1

你不需要通过 json 对象名来获取这个数组。 意味着您必须在此处使用 Object 键。

//JSONObject c = Jsonobj.getJSONObject("row");
//convert your jsonarray in json object
Iterator<String> it = c.keys();// check for first and next object
while (it.hasNext()) { // call while we have next object in array
String Key = it.next(); // this will get next obj name in string "c"
JSONObject keyobj = new JSONObject(c.toString()); // this will gat "c" object array from json

1. 在 Json 对象中获取“行”数组
2. 现在不获取对象“c”，而是在这里使用对象键方法
3. 检查直到“行”数组没有任何对象
4. 在您的 JSON 中，此方法将调用两次，您将轻松获得具有相同对象名称的所有数据

Answer 2

@abc 请用这个方法。它会解决你的问题。如果有任何问题，请在下方评论。

private void json(String jsonString) {
arrayList = new ArrayList<>();
JSONObject mainObj = null;
try {
  mainObj = new JSONObject(jsonString);
} catch (JSONException e) {
  e.printStackTrace();
}
String Name = null;

if (mainObj != null) {
  try {
    JSONObject tableObject = mainObj.getJSONObject("table");
      JSONArray rowMasterArray = tableObject.getJSONArray("rows");          
      if (rowMasterArray != null) {
        for (int i = 0; i < rowMasterArray.length(); i++) {
          JSONObject rowsObject= rowMasterArray.getJSONObject(i);
          if (rowsObject != null) {
              JSONArray rowsItemArray = rowsObject.getJSONArray("c");
              if (rowsItemArray != null) {
                for (int k = 0; k < rowsItemArray.length(); k++) {
                  JSONObject innerElem = rowsItemArray.getJSONObject(k);
                  if (innerElem != null) {
                    Name = innerElem.getString("v");
                    arrayList.add(Name);
                    Log.i("arrayList", "" + arrayList);
                  }
                }
              }
          }
        }
      }
  }catch (JSONException e) {
      e.printStackTrace();
    }
  }
}

Answer 3

我得到了我的问题的解决方案。我对 getSpreadSheetData() 方法做了一些更改。
在这里我犯了一些逻辑错误，现在它解决了

public void getSpreadSheetData() {
        hashMap = new HashMap<Integer, String>();
        String result = getSpreadSheetResponce();
        List<String> arrayList = new ArrayList<String>();
        if (result == null) {
            Log.e("net not present:", "");
        } else {
            int start = result.indexOf("{", result.indexOf("{") + 1);
            int end = result.lastIndexOf("}");
            String jsonResponse = result.substring(start, end);

            try {
                JSONObject mainObj = new JSONObject(jsonResponse);
                String Name = null;

                if (mainObj != null) {
                    JSONArray list = mainObj.getJSONArray("rows");
                    if (list != null) {
                        for (int i = 0; i < list.length(); i++) {
                            JSONObject innerJsonObject = list.getJSONObject(i);
                            if (innerJsonObject != null) {
                                //
                                JSONArray valuesJsonArray = innerJsonObject
                                        .getJSONArray("c");
                                if (valuesJsonArray != null) {
                                    for (int j = 0; j < 1; j++) {
                                        JSONObject innerElem = valuesJsonArray
                                                .getJSONObject(j);
                                        if (innerElem != null) {
                                            Name = innerElem.getString("v");
                                            // arrayList.add(Name);
                                            Log.e("name no:",
                                                    "" + Name.toString());
                                            JSONObject SecondElement = valuesJsonArray
                                                    .getJSONObject(j + 1);
                                            if (SecondElement != null) {
                                                String phone = SecondElement
                                                        .getString("f");
                                                Log.e("Phone no:",
                                                        "" + phone.toString());
                                            }
                                        }
                                    }
                                }
                            }
                        }
                    }
                }
                Log.e("Name Last", "" + Name);
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }

    }