【发布时间】:2014-09-02 16:44:25
【问题描述】:
我在ListView 中显示朋友列表,并在EditText 上设置TextWatcher 以允许搜索。这适用于 1 个限制(我没有得到):输入一个字符正确过滤列表,删除一个字符但没有做任何事情。当输入为空时,原始列表正确显示,但是Filter 也应该在删除字符时起作用,因为onTextChanged() 被调用。我哪里错了?
类 (BaseAdapter) 字段:
private ArrayList<User> friends;
private ArrayList<User> originalFriendList;
//to keep track of the original list
this.originalFriendList = friends;
过滤器类:
private class FriendSearchFilter extends Filter {
@Override
protected FilterResults performFiltering(CharSequence constraint) {
FilterResults results = new FilterResults();
if (constraint != null && constraint.length() > 0) {
ArrayList<User> filterList = new ArrayList<User>();
for (User friend : friends) {
if (StringUtils.containsIgnoreCase(friend.getLast_name(), constraint)
|| StringUtils.containsIgnoreCase(friend.getFirst_name(), constraint)) {
filterList.add(friend);
}
}
results.count = filterList.size();
results.values = filterList;
} else {
// the input is empty
results.count = originalFriendList.size();
results.values = originalFriendList;
}
return results;
}
@Override
@SuppressWarnings("unchecked")
protected void publishResults(CharSequence constraint, FilterResults results) {
friends = (ArrayList<User>) results.values;
notifyDataSetChanged();
}
}
TextWatcher:
etSearch.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence charSequence, int start,
int before, int count) {
/* no action required */
}
@Override
public void onTextChanged(CharSequence charSequence, int start, int count, int after) {
if(mFriendListFrag == null || !mFriendListFrag.equals(mFragAdapter.getItem(mViewPager.getCurrentItem())));
mFriendListFrag = (FriendListFragment) mFragAdapter.getItem(mViewPager.getCurrentItem());
mFLAdapter = (FriendListAdapter) mFriendListFrag.getListAdapter();
mFLAdapter.getFilter().filter(charSequence.toString());
Log.e("ON", "TEXT CHANGED");
}
@Override
public void afterTextChanged(Editable editable) {
/* no action required */
}
});
【问题讨论】:
标签: android android-filter android-filterable