如何关闭弹出窗口？

Question

我的活动中有PopupWindow。但是，PopupWindow 在与我的活动交互后不会被关闭。

当我在不是PopupWindow的屏幕上触摸/滚动/单击/等时，我想关闭弹出窗口。

public class ListViewForDeleteContact extends AppCompatActivity {
    ListView myListView;
    protected  void onCreate(Bundle savedInstanceState){
        super.onCreate(savedInstanceState);
        setContentView(R.layout.listviewfordeletecontactlayout_main);

        myListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                LayoutInflater layoutInflater=(LayoutInflater)ListViewForDeleteContact.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                View dfg= layoutInflater.inflate(R.layout.popupwindowfordeletelayout_main,(ViewGroup)findViewById(R.id.popupId));
                PopupWindow popupWindow=new PopupWindow(dfg,420,300,true);

                popupWindow.showAtLocation(dfg, Gravity.CENTER, 0, 0);
                popupWindow.setOutsideTouchable(true);

            }
        });
    }
}

我尝试了一些方法，例如 setOutsideTouchable(true); 和 setBackgroundDrawable(true)，但对我不起作用。

Answer 1

 First add
 popupWindow.setOutsideTouchable(true);
and use 
popupWindow.setBackgroundDrawable(new BitmapDrawable(getResources(),
            ""));
or 

popupWindow.setOnDismissListener(new PopupWindow.OnDismissListener() {

    @Override
    public void onDismiss() {
        popupWindow.dismiss();

    }
});