无法将数据插入 android studio sqlite 数据库答案

【问题标题】：Unable to insert data into android studio sqlite database无法将数据插入 android studio sqlite 数据库
【发布时间】：2021-02-26 03:03:31
【问题描述】：

我目前正在做一个学校项目，试图创建一个送餐服务，并且需要一个注册/登录数据库。但是在创建/将数据插入数据库时遇到了麻烦。应用没有崩溃，但 Toast 消息告诉我“注册失败。”。

从错误日志看来，我可以创建表，但无法将数据插入表中。

如果有人能给我一些建议，我将不胜感激。

DatabaseHelper.java

public class DatabaseHelper extends SQLiteOpenHelper {
public static final String DATABASE_NAME = " mylist.db ";
public static final String TABLE_NAME = " mylist ";
public static final String USER_NAME = " username ";
public static final String EMAIL = " email ";
public static final String PHONE_NUMBER = " phone ";
public static final String PASSWORD = " password ";

public DatabaseHelper(Context context) {
    super(context, DATABASE_NAME, null, 1);
}

//CREATING THE DATABASE TABLE
@Override
public void onCreate(SQLiteDatabase sqLiteDatabase) {
    String createTable;
    createTable = "CREATE TABLE " + TABLE_NAME +
            " ( ID INTEGER PRIMARY KEY AUTOINCREMENT, "+
            USER_NAME + " username " +
            EMAIL + " email ," +
            PHONE_NUMBER + " phone ,"+
            PASSWORD + " password ) ";
    sqLiteDatabase.execSQL(createTable);
}

@Override
public void onUpgrade(SQLiteDatabase sqLiteDatabase, int i, int i1) {
sqLiteDatabase.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
}

public boolean addData(String username, String email, String phone, String password){
SQLiteDatabase sqLiteDatabase = this.getWritableDatabase();
ContentValues contentValues = new ContentValues();
contentValues.put(USER_NAME, username);
contentValues.put(EMAIL, email);
contentValues.put(PHONE_NUMBER, phone);
contentValues.put(PASSWORD, password);
long result = sqLiteDatabase.insert(TABLE_NAME, null, contentValues);
    if (result == -1) return false;
else {return true;}
}

}

错误日志

    E/SQLiteLog: (1) table mylist has no column named email
E/SQLiteDatabase: Error inserting  phone =  email =  password =  username =j
    android.database.sqlite.SQLiteException: table mylist has no column named email (code 1): , while compiling: INSERT INTO  mylist ( phone , email , password , username ) VALUES (?,?,?,?)
        at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method)
        at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:890)
        at android.database.sqlite.SQLiteConnection.prepare(SQLiteConnection.java:501)
        at android.database.sqlite.SQLiteSession.prepare(SQLiteSession.java:588)
        at android.database.sqlite.SQLiteProgram.<init>(SQLiteProgram.java:58)
        at android.database.sqlite.SQLiteStatement.<init>(SQLiteStatement.java:31)
        at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1546)
        at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1417)
        at com.example.doonfood.DatabaseHelper.addData(DatabaseHelper.java:45)
        at com.example.doonfood.signuppage.ADDDATA(signuppage.java:33)
        at com.example.doonfood.signuppage.Signup(signuppage.java:48)
        at java.lang.reflect.Method.invoke(Native Method)
        at androidx.appcompat.app.AppCompatViewInflater$DeclaredOnClickListener.onClick(AppCompatViewInflater.java:409)
        at android.view.View.performClick(View.java:6294)
        at com.google.android.material.button.MaterialButton.performClick(MaterialButton.java:992)
        at android.view.View$PerformClick.run(View.java:24770)
        at android.os.Handler.handleCallback(Handler.java:790)
        at android.os.Handler.dispatchMessage(Handler.java:99)
        at android.os.Looper.loop(Looper.java:164)
        at android.app.ActivityThread.main(ActivityThread.java:6494)
        at java.lang.reflect.Method.invoke(Native Method)
        at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:438)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:807)

signuppage.java

public class signuppage extends AppCompatActivity {

DatabaseHelper myDB;
EditText SignupUserName;
EditText SignupEMail;
EditText SignupPhoneNumber;
EditText SignupPassword;
Button SignupBtn;

@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.signuppage);
    myDB = new DatabaseHelper(this);
    SignupUserName = findViewById(R.id.SignupUserName);
    SignupEMail = findViewById(R.id.SignupEMail);
    SignupPhoneNumber = findViewById(R.id.SignupPhoneNumber);
    SignupPassword = findViewById(R.id.SignupPassword);
    SignupBtn = findViewById(R.id.SignupBtn);
}

public void ADDDATA(String newUSER, String newEMAIL, String newPHONE, String newPASSWORD){
    boolean insertData = myDB.addData(newUSER, newEMAIL, newPHONE, newPASSWORD);
    if (insertData == true){
        Toast.makeText(signuppage.this, "Sign up successful.", Toast.LENGTH_SHORT).show();
    }else {
        Toast.makeText(signuppage.this, "Sign up unsuccessful.", Toast.LENGTH_SHORT).show();
    }
}

public void Signup(View view) {
    String newUSER, newEMAIL, newPHONE, newPASSWORD;
    newUSER = SignupUserName.getText().toString();
    newEMAIL = SignupEMail.getText().toString();
    newPHONE = SignupPhoneNumber.getText().toString();
    newPASSWORD = SignupPassword.getText().toString();
    if ((SignupUserName.length() != 0) || (SignupEMail.length() != 0) || (SignupPhoneNumber.length() != 0) || (SignupPassword.length() != 0)) {
        ADDDATA(newUSER, newEMAIL, newPHONE, newPASSWORD);
        SignupUserName.setText(newUSER);
        SignupEMail.setText(newEMAIL);
        SignupPhoneNumber.setText(newPHONE);
        SignupPassword.setText(newPASSWORD);
    } else {
        Toast.makeText(signuppage.this, "Text Field cannot be empty.", Toast.LENGTH_SHORT).show();
    }
}

}

【问题讨论】：

标签： java android sqlite android-sqlite

【解决方案1】：

首先，删除 db/table/columns 名称的变量定义中的前导和尾随空格：

public static final String DATABASE_NAME = "mylist.db";
public static final String TABLE_NAME = "mylist";
public static final String ID = "ID"; // I added this definition
public static final String USER_NAME = "username";
public static final String EMAIL = "email";
public static final String PHONE_NUMBER = "phone";
public static final String PASSWORD = "password";

然后，修复表的 CREATE 语句，其中没有定义列的数据类型，而是使用了两次它们的名称，并且还漏掉了中间的逗号：

createTable = "CREATE TABLE " + TABLE_NAME + "(" +
              ID + " INTEGER PRIMARY KEY AUTOINCREMENT, " +
              USER_NAME + " TEXT," +
              EMAIL + " TEXT," +
              PHONE_NUMBER + " TEXT," +
              PASSWORD + " TEXT)";

进行这些更改后，您必须从设备上卸载应用程序，以便删除数据库并重新运行以重新创建数据库和表。

【讨论】：

关于 CREATE 语句的问题。 SQLite 代码（绿色）是否对间距敏感？
@JoelDong-JoeSuh 对间距敏感是什么意思？
" TEXT, " 有效，带有前导和尾随空格。虽然“TEXT”不起作用，但用户将无法注册
@JoelDong-JoeSuh 当你定义一个列时，你会这样做：columnname datatype，所以列名（不能包含空格）和数据类型之间必须有一个空格.如果没有空格，那么你有类似：IDTEXT，它在 SQLite 中是有效的，但它被认为只是没有数据类型的列的名称。
哦，这解释了很多，谢谢你的解释。

【解决方案2】：

首先，你不需要在数据库名称中写.db。
在onCreate()中这样写

String query = "Create table if not exists " + TABLE_NAME + " (UESR_NAME, EMAIL, PHONE_NUMBER,PASSWORD)"; db.execSQL(query);
创建一个在表中插入数据的方法，如下所示： public void insertData(String userName, String email, String phoneNumber, String password) { SQLiteDatabase db = getWritableDatabase(); ContentValues values = new ContentValues(); values.put("USER_NAME", userName); values.put("EMAIL", email); values.put("PHONE_NUMBER",phoneNumber); values.put("PASSWORD",password); db.insert(TABLE_NAME,null,values); db.close(); }

【讨论】：