BroadcastReceiver的onReceive方法没有被调用答案

【问题标题】：BroadcastReceiver's onReceive method is not calledBroadcastReceiver的onReceive方法没有被调用
【发布时间】：2015-10-22 22:50:34
【问题描述】：

我有一个内部有 Fragment 和 IntentService 的 Activity。当我单击按钮对话框片段打开并输入我的数据。之后，我单击 Ok 并调用 getActivity().startService(intent)。服务通过 LocalBroadcastManager 调用 sendBroadcast(intent)，但未调用 onReceive() 方法。怎么了？这是我的广播接收器

private BroadcastReceiver mApiBroadcastReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        Log.d("tag", intent.getAction());
        switch (intent.getAction()) {
            case "register":
                showMessage(intent.getStringExtra(ApiService.EXTRA_ANSWER));
                break;
            case "authorize":
                showProfile((User) intent.getParcelableExtra(ApiService.EXTRA_USER));
                break;
            default:
                break;
        }
    }
};

我在这里注册接收器

@Override
protected void onResume() {
    super.onResume();    
    LocalBroadcastManager.
        getInstance(this).
        registerReceiver(mApiBroadcastReceiver, new IntentFilter(ApiService.API_BROADCAST));
}

我的 onDestroy 方法

 @Override
protected void onPause() {
    super.onPause();

    LocalBroadcastManager.getInstance(this).unregisterReceiver(mApiBroadcastReceiver);
}

以及我在服务中发送广播的方法

private void sendMessage(Object answer) {
    Intent intent = new Intent(API_BROADCAST);
    if (answer instanceof String) {
        intent.setAction("register");
        Log.d("tag", answer.toString());
        intent.putExtra(EXTRA_ANSWER, answer.toString());

    } else if (answer instanceof User) {
        intent.setAction("authorize");
        intent.putExtra(EXTRA_USER, (User) answer);
    }
    LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}

【问题讨论】：

标签： android android-broadcast localbroadcastmanager android-broadcastreceiver

【解决方案1】：

你不应该打电话给intent.setAction()。

你正在监听 Intents with action ApiService.API_BROADCAST:

注册时使用new IntentFilter(ApiService.API_BROADCAST);
广播时使用new Intent(ApiService.API_BROADCAST);

没关系，但如果您稍后调用intent.setAction("register")，您将覆盖您设置的第一个操作。

尝试将子操作字符串作为Extra 传递：

private void sendMessage(Object answer) {
    Intent intent = new Intent(API_BROADCAST);
    if (answer instanceof String) {
        intent.putExtra(EXTRA_WHAT, "register");
        intent.putExtra(EXTRA_ANSWER, answer.toString());

    } else if (answer instanceof User) {
        intent.putExtra(EXTRA_WHAT, "authorize");
        intent.putExtra(EXTRA_USER, (User) answer);
    }
    LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}

【讨论】：