【发布时间】:2019-09-27 10:36:19
【问题描述】:
我尝试了以下 firebase 官方动态链接示例,但对我不起作用。
主祭:
<activity android:name=".java.MainActivity" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<!-- [START link_intent_filter] -->
<intent-filter >
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE"/>
<data
android:host="plpsoft.page.link"
android:scheme="https"/>
<data
android:host="plpsoft.page.link"
android:scheme="http"/>
</intent-filter>
<!-- [END link_intent_filter] -->
</activity>
活动:
@Override
protected void onCreate(Bundle savedInstanceState) {
FirebaseDynamicLinks.getInstance()
.getDynamicLink(getIntent())
.addOnCompleteListener(new OnCompleteListener<PendingDynamicLinkData>() {
@Override
public void onComplete(@NonNull Task<PendingDynamicLinkData> task) {
Uri deepLink = null;
if (task.getResult() != null) {
deepLink=task.getResult().getLink();
((TextView) findViewById(R.id.linkViewReceive))
.setText(deepLink.toString());
}
}
})
.addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
@Override
public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
// Get deep link from result (may be null if no link is found)
Uri deepLink = null;
if (pendingDynamicLinkData != null) {
deepLink = pendingDynamicLinkData.getLink();
}
// Handle the deep link. For example, open the linked
// content, or apply promotional credit to the user's
// account.
// ...
// [START_EXCLUDE]
// Display deep link in the UI
if (deepLink != null) {
Snackbar.make(findViewById(android.R.id.content),
"Found deep link!", Snackbar.LENGTH_LONG).show();
((TextView) findViewById(R.id.linkViewReceive))
.setText(deepLink.toString());
} else {
Log.d(TAG, "getDynamicLink: no link found");
}
// [END_EXCLUDE]
}
})
.addOnFailureListener(this, new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Log.e("Splash", "getDynamicLink:onFailure", e);
}
})
.addOnFailureListener(this, new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Log.w(TAG, "getDynamicLink:onFailure", e);
}
});
}
点击 URL 时,应用程序将成功启动,并且我还获得了意图数据 URI 字符串。如果我将此 URI 传递给 getDynamicLink() 方法,它将返回为 null。我还在 Firebase 控制台中添加了 SHA1 和 SHA256 键。
【问题讨论】:
-
得到与我们在 Android 应用程序中提取 firebase 深层链接 url 相同的错误。谁有同样的经历,请帮忙。
-
我只能使用以下方法获取链接:Uri link = getIntent().getData() 不成功:FirebaseDynamicLinks.getInstance().getDynamicLink(getIntent())
标签: android firebase firebase-dynamic-links