过滤列表后点击 ListView Item

Question

我为我的学习做了一些项目，我想使用edittext创建列表视图搜索，它工作得很好。问题是当列表视图被过滤时，我尝试单击结果它会执行错误的操作。

然后我意识到这是因为我在点击操作时使用了列表视图位置，所以我尝试将其更改为列表视图值，但这对我来说非常困难，因为我在下面的代码中总是遇到错误。

@Override
public void onItemClick(AdapterView<?> parent, View view, final int position, long id) {
    TextView textView = (TextView) view;
    String parameterNilai = String.valueOf(textView.getText());

    if (parameterNilai.equals("One")) {
        try {
            Intent intent = new Intent(MurotalActivity.this, com.ummi.myapplication.speaker.MurotalActivityDetail.class);
            intent.putExtra("TAG_SID", "229");
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
            closeKeyboard();
            finish();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (IllegalStateException e) {
            e.printStackTrace();
        }
    } else if (parameterNilai.equals("Two")) {
        try {
            Intent intent = new Intent(MurotalActivity.this, com.ummi.myapplication.speaker.MurotalActivityDetail.class);
            intent.putExtra("TAG_SID", "230");
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
            closeKeyboard();
            finish();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (IllegalStateException e) {
            e.printStackTrace();
        }
    } else if (parameterNilai.equals("Three")) {
        try {
            Intent intent = new Intent(MurotalActivity.this, com.ummi.myapplication.speaker.MurotalActivityDetail.class);
            intent.putExtra("TAG_SID", "231");
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
            closeKeyboard();
            finish();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (IllegalStateException e) {
            e.printStackTrace();
        }
    }

对于列表数组如下：

<string-array name="listsurah">
    <item>One</item>
    <item>Two</item>
    <item>Three</item>
</string-array>

我的布局 XML：

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent"
xmlns:app="http://schemas.android.com/apk/res-auto"
tools:context=".MurotalActivity"
xmlns:tools="http://schemas.android.com/tools">
<RelativeLayout
    android:id="@+id/judul1"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:layout_gravity="center"
    android:background="#A6E0BA"
    android:gravity="center_vertical">
    <EditText android:id="@+id/inputSearch"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:hint="Cari Surat.."
        android:inputType="textVisiblePassword"/>
</RelativeLayout>
<FrameLayout
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:layout_below="@id/judul1"
    android:orientation="vertical">

    <ScrollView
        android:layout_width="match_parent"
        android:layout_height="match_parent">

        <RelativeLayout
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:orientation="horizontal">

            <ListView
                android:id="@+id/listview"
                android:layout_width="match_parent"
                android:layout_height="9600dp"
                android:layout_marginBottom="20dp"
                android:choiceMode="singleChoice"
                android:listSelector="#F0BCBC">
            </ListView>
        </RelativeLayout>
    </ScrollView>

我从 logcat 得到的错误：

2020-03-19 06:14:37.593 30929-30929/com.mby.mbaca E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.mby.mbaca, PID: 30929
java.lang.ClassCastException: android.widget.LinearLayout cannot be cast to android.widget.TextView
    at com.ummi.myapplication.MurotalActivity.onItemClick(MurotalActivity.java:109)
    at android.widget.AdapterView.performItemClick(AdapterView.java:318)
    at android.widget.AbsListView.performItemClick(AbsListView.java:1159)
    at android.widget.AbsListView$PerformClick.run(AbsListView.java:3136)
    at android.widget.AbsListView$3.run(AbsListView.java:4052)
    at android.os.Handler.handleCallback(Handler.java:873)
    at android.os.Handler.dispatchMessage(Handler.java:99)
    at android.os.Looper.loop(Looper.java:193)
    at android.app.ActivityThread.main(ActivityThread.java:6669)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:493)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:858)

基于上面的logcat问题就出在了

TextView textView = (TextView) view;

请需要任何人的帮助，我如何根据 ListItem 文本值而不是位置单击 ListItem

Answer 1

对@Kiryl Tkach 的回答稍作修改，我通过添加成功做到了这一点：

String parameterNilai = listView.getItemAtPosition(position).toString();

所以我对 onItemClick 的完整代码是：

public void onItemClick(AdapterView<?> parent, View view, final int position, long id) {
    String parameterNilai = listView.getItemAtPosition(position).toString();

    if (parameterNilai.equals("One")) {
        try {
            Intent intent = new Intent(MurotalActivity.this, com.ummi.myapplication.speaker.MurotalActivityDetail.class);
            intent.putExtra("TAG_SID", "229");
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
            closeKeyboard();
            finish();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (IllegalStateException e) {
            e.printStackTrace();
        }
    } else if (parameterNilai.equals("Two")) {
        try {
            Intent intent = new Intent(MurotalActivity.this, com.ummi.myapplication.speaker.MurotalActivityDetail.class);
            intent.putExtra("TAG_SID", "230");
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
            closeKeyboard();
            finish();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (IllegalStateException e) {
            e.printStackTrace();
        }
    } else if (parameterNilai.equals("Three")) {
        try {
            Intent intent = new Intent(MurotalActivity.this, com.ummi.myapplication.speaker.MurotalActivityDetail.class);
            intent.putExtra("TAG_SID", "231");
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
            closeKeyboard();
            finish();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (SecurityException e) {
            e.printStackTrace();
        } catch (IllegalStateException e) {
            e.printStackTrace();
        }
    }
}

希望这可以回答类似的问题

Answer 2

您的项目元素是 LinearLayout，而不是 TextView。正确地，您应该按位置获取集合元素（为此，您有位置变量）并从中获取文本。类似的东西

字符串文本 = 适配器.getItem(位置)