列表视图选择开始一个新的活动

Question

所以我正在使用列表视图来尝试在选择某个项目时打开特定的活动。这是我现在正在使用的代码。我知道它是错误的，但不确定我需要改变它以使其工作。我想我需要一个意图并尝试了一些想法，但没有想出太多。谢谢。

package table.periodic;

import android.app.ListActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class List extends ListActivity{



String[] elements={"actinium", "aluminum", "americium", 
        "antimony", "argon", "arsenic", "astatine", "barium", 
        "berkelium", "beryllium", "bismuth", "bohrium", "boron", 
        "bromine", "cadmium", "calcium", "californium", "carbon", 
        "cerium", "cesium", "chlorine", "chromium", "cobalt", 
        "copper", "copernicium", "curium", "darmstadtium", "dubnium", 
        "dysprosium", "einsteinium", "erbium", "europium", "fermium", 
        "fluorine", "francium", "gadolinium", "gallium", "germanium", 
        "gold", "hafnium", "hassium", "helium", "holmium", 
        "hydrogen", "indium", "iodine", "iridium", "iron", 
        "krypton", "lanthanum", "lawrencium", "lead", "lithium", 
        "lutetium", "magnesium", "manganese", "meitnerium", "mendelevium", 
        "mercury", "molybdenum", "neodymium", "neon", "neptunium", 
        "nickel", "niobium", "nitrogen", "nobelium", "osmium", 
        "oxygen", "palladium", "phosphorus", "platinum", "plutonium", 
        "polonium", "potassium", "praseodymium", "promethium", "protactinium", 
        "radium", "radon", "rhenium", "rhodium", "roentgenium", "rubidium", 
        "ruthenium", "rutherfordium", "samarium", "scandium", "seaborgium", 
        "selenium", "silicon", "silver", "sodium", "strontium", "sulfur", 
        "tantalum", "technetium", "tellurium", "terbium", "thallium", "thorium", 
        "thulium", "tin", "titanium", "tungsten", "ununhexium", "ununoctium", 
        "ununpentium", "ununquadium", "ununseptium", "ununtrium", "uranium", 
        "vanadium", "xenon", "ytterbium", "yttrium", "zinc", "zirconium"};

 public void onCreate(Bundle icicle) {
    super.onCreate(icicle);
    setContentView(R.layout.list); 
    setListAdapter(new ArrayAdapter<String>(
            this, android.R.layout.simple_list_item_1, 
            elements));

 }

 public void onListItemClick(ListView parent, View v, int position,
         long id){


     if ("actinium".equals(elements[position]))
        {startActivity(Actinium.class);}

     else if ("aluminum".equals(elements[position]))
        {startActivity(Aluminum.class);}



 }

Answer 1

我对您的代码进行了一些编辑。您需要在布局 XML 文件中创建一个 ListView 元素，然后在 Java 文件中使用 findViewById 找到它：

import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class List extends Activity {

    String[] elements = { … };  // (omitted for better legibility)

    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);

        setContentView(R.layout.main); 
        ListView lv = (ListView)findViewById(R.id.ListView01);
        lv.setAdapter(new ArrayAdapter<String>(
                this, android.R.layout.simple_list_item_1, 
                elements));
    }

    public void onListItemClick(ListView parent, View v, int position,
                                 long id) {
        //if ("actinium".equals(elements[position]))
        //    {startActivity(Actinium.class);}
        //else if ("aluminum".equals(elements[position]))
        //    {startActivity(Aluminum.class);}
    }
}