在可点击的列表视图中搜索时如何恢复旧位置？

Question

我正在开发一个具有可点击列表视图的应用程序。我在列表视图上方创建了一个搜索过滤器，它运行良好。当我点击不同的项目时，我会在另一个很好的活动中获得它们的相应详细信息。但是，当我使用搜索过滤器搜索同一项目时，我会在其他位置获取详细信息。怎么找回原来的位置？这是我的代码：

代码：

public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
    // TODO Auto-generated method stub

    //we use the items of the listview as title of the next activity
    String course = listAdapter.getItem(position);

    //we retrieve the description of the juices from an array defined in arrays.xml
    String[] description = getResources().getStringArray(R.array.description);
    final String courselabel = description[position];

    //retrieve content for the dialog
    String[] dialogmessage = getResources().getStringArray(R.array.dialogmessage);
    final String dialogmsg = dialogmessage[position];

    Intent intent = new Intent(getApplicationContext(), MainActivityas.class);
    intent.putExtra("message", message);
    startActivity(intent);
}

Answer 1

在开始时使 postiion=0 并在 onclick 中更新位置值

@Override
 public void onResume() {
 super.onResume();  // Always call the superclass method first
 listView.setSelection(position);
}

Answer 2

另一种方法是使用startActivityForResult() 和onActivityResult() 我觉得这个比较有用。

假设您使用的是 Activity1 和 Activity2。

在 Activity1 中启动 Activity2：

public static final String ACT2 = "ACT2";
public static final String POS = "POS";
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
    // TODO Auto-generated method stub

    someAction(position);
}

public void someAction(int position){

    //we use the items of the listview as title of the next activity
    String course = listAdapter.getItem(position);

    //we retrieve the description of the juices from an array defined in arrays.xml
    String[] description = getResources().getStringArray(R.array.description);
    final String courselabel = description[position];

    //retrieve content for the dialog
    String[] dialogmessage = getResources().getStringArray(R.array.dialogmessage);
    final String dialogmsg = dialogmessage[position];


    Intent intent = new Intent(this, Activity2.class).setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    intent.putExtra(POS,lv.getPosition());
    intent.putExtra("message", message);
    startActivityForResult(intent, _.ACT2);
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK) {
        lv.setPosition(mPosition);//HERE POSITION SETUP
    }
}

在 Activity2 中：

@Override
public int mPosition = 0;
    protected void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    Intent data = getIntent();
    String msg =data.getStringExtra("message", "");
    mPosition = data.getIntExtra(Activity1.POS, mPosition);
}

@Override
public void finish() {     

    Intent data = new Intent();
    data.putExtra(Activity1.POS,mPosition);
    setResult(RESULT_OK, data); 

    super.finish();
}