【发布时间】:2015-08-28 02:55:57
【问题描述】:
我正在使用 google 搜索实现来搜索用户在单击按钮时输入的结果。
我听那个按钮点击并获取/解析 JSON 结果。
我已经解析了 JSON 的“标题”和“url”,并希望将其填充到 ListView。
但是,我认为我没有正确使用 ArrayAdapter 类。
MyActivity.java:
私有 ListView listViewGoogle;
private String[] resultArray;
private EditText searchBox;
private Button searchBtn;
private String search_url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=";
private String search_query;
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_my);
listViewGoogle = (ListView)findViewById(R.id.listviewgoogle);
searchBox = (EditText)findViewById(R.id.searchBox);
searchBtn = (Button)findViewById(R.id.searchBtn);
searchBtn.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View v)
{
new JsonSearchTask().execute();
try
{
search_query = search_url + searchBox.getText().toString();
new JsonSearchTask().execute();
ArrayAdapter adapter = new ArrayAdapter<String>(this, R.layout.activity_listviewgoogle, resultArray);
listViewGoogle.setAdapter(adapter);
}
catch (Exception e)
{
// TODO: handle exception
}
}
});
}
private class JsonSearchTask extends AsyncTask<Void, Void, Void>
{
@Override
protected Void doInBackground(Void... arg0)
{
try
{
parseResult(sendQuery(search_query));
}
catch (JSONException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
}
private String sendQuery(String query) throws IOException
{
String queryResult = "";
URL searchURL = new URL(query);
HttpURLConnection httpURLConnection = (HttpURLConnection) searchURL.openConnection();
if (httpURLConnection.getResponseCode() == HttpURLConnection.HTTP_OK)
{
InputStreamReader inputStreamReader = new InputStreamReader(httpURLConnection.getInputStream());
BufferedReader bufferedReader = new BufferedReader(inputStreamReader, 8192);
String line = null;
while ((line = bufferedReader.readLine()) != null)
{
queryResult += line;
}
bufferedReader.close();
}
return queryResult;
}
private void parseResult(String json) throws JSONException
{
String parsedResult = "";
JSONObject jsonObject = new JSONObject(json);
JSONObject jsonObject_responseData = jsonObject.getJSONObject("responseData");
JSONArray jsonArray_results = jsonObject_responseData.getJSONArray("results");
resultArray = new String[jsonArray_results.length()];
for(int i = 0; i < jsonArray_results.length(); i++)
{
JSONObject jsonObject_i = jsonArray_results.getJSONObject(i);
parsedResult = "title: " + jsonObject_i.getString("title") + "\n";
parsedResult += "url: " + jsonObject_i.getString("url") + "\n";
//parsedResult += "\n";
resultArray[i] = parsedResult;
}
}
activity_listviewgoogle.xml:
<TextView xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/label"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="10dip"
android:textSize="16dip"
android:textStyle="bold"
android:gravity="center" >
</TextView>
activity_my.xml:
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="horizontal"
android:id="@+id/parentOuter" >
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<EditText
android:layout_width="fill_parent"
android:layout_height="match_parent"
android:hint="type to search..."
android:layout_weight="2"
android:id="@+id/searchBox" />
<Button
android:layout_width="match_parent"
android:layout_height="match_parent"
android:text="Search Me!"
android:layout_weight="2"
android:id="@+id/searchBtn" />
<ListView
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/listviewgoogle"
android:layout_weight="1" />
</LinearLayout>
</LinearLayout>
我似乎遇到了这个错误:
错误:(71, 44) 错误: 没有找到合适的构造函数 ArrayAdapter(,int,String[]) 构造函数 ArrayAdapter.ArrayAdapter(Context,int,int) 不适用(参数 不匹配;不能转换为上下文) 构造函数 ArrayAdapter.ArrayAdapter(Context,int,String[]) 不是 适用(参数不匹配;不能 转换为 Context) 构造函数 ArrayAdapter.ArrayAdapter(Context,int,List) 不适用 (参数不匹配;无法转换为 上下文)
有没有办法使用 ArrayAdapter 用数据填充ListView,或者还有其他方法吗?
抱歉,我是安卓新手。
【问题讨论】:
标签: java android listview android-arrayadapter