2 ListView中的一个ListFragment只有一个onListItemClick

Question

正如我在标题中提到的，我在 ListFragment 中有 2 个 ListView（我们称它们为 A 和 B），并且只有一个 onListItemClick。

当我单击列表 A 的一行时，我的 onListItemClick 调用正常。但是当我点击列表 B 的一行时，什么也没有发生。

这就是我所拥有的：

<!-- LIST A -->
<ListView
    android:id="@id/android:list"
    android:layout_width="match_parent"
    android:layout_height="wrap_content" >
</ListView>

<!-- Separator -->
<View
    android:layout_width="fill_parent"
    android:layout_height="1dp"
    android:background="@android:color/darker_gray"/>

<!-- LIST B -->
<ListView
    android:id="@+id/listCompany"
    android:layout_width="match_parent"
    android:layout_height="wrap_content" >
</ListView>

这是我的 ListFragment：

public class ClientsActivity extends ListFragment {
    OnClientSelectedListener mClientListener;


public interface OnClientSelectedListener {
        public void onEmployeeSelected(int id);
        public void onCompanySelected(int id);
    }

@Override
    public void onAttach(Activity activity) {
        super.onAttach(activity);
        try {
        mClientListener = (OnClientSelectedListener) activity;
        } catch (ClassCastException e) {
            throw new ClassCastException(activity.toString() + " you must implement OnClientSelectedListener ");
    }
}

@Override
    public void onListItemClick(ListView l, View v, int position, long id) {
    super.onListItemClick(l, v, position, id);

    Log.e("onListItemClick","called with " + position + " : "+l.getId() + " and " + android.R.id.list);
        int id = position; 
    if (l.getId() == android.R.id.list) {
           mClienteListener.onEmployeeSelected(id);
       } else if (l.getId() == R.id.listCompany) {
           mClienteListener.onCompanySelected(id);
       }
}

然后在我的主 FragmentActivity 中实现接口 OnClientSelectedListener。我认为这必须与我的 ListViews 中的 android:id 一起使用。当单击列表 B 的一行时，我不知道如何调用 onListItemClick。任何帮助将不胜感激。

解决方案：

在我的 ListFragment 的 onCreateView 中，我有：

 public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {

    View view = inflater.inflate(R.layout.activity_clientes, container, false);

            //LIST A
    listEmploees(view);

            //LIST B
    listCompanies(view);
...
}

private void listCompanies(View view){
    CompanyqliteDao companyDao = new CompanyqliteDao ();
            //I get all the companies from DB
    mCursorCompany = companyDao.listCompany(getActivity());

    if(mCursorCompany.getCount()>0){
        String[] from = new String[] { "name", "phone"};
        int[] to = new int[] { R.id.textViewNameIzq,  R.id.textViewNameCent };
        ListView lvCompanies = (ListView) view.findViewById (R.id.listCompany);

                    //I have a custom adapter
        ListClientCursorAdapter notes = new ListClientsCursorAdapter(contexto, R.layout.activity_fila_cliente, mCursorCompany, from, to, 0);
        lvCompanies .setAdapter(notes);


        lvCompanies.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapter, View view, int position, long arg)   {
                onListItemClick(lvCompanies,view,position,arg);
            }
        });

    }
}


private void listEmploees(View view){
    EmployeeSqliteDao employeeDao = new EmployeeSqliteDao();
            //Get the list from DB
    mCursorEmployee = employeeDao.listEmployees(getActivity());

    if(mCursorEmployee.getCount()>0){
        String[] from = new String[] { "name", "phone"};
        int[] to = new int[] { R.id.textViewNameIzq,  R.id.textViewNameCent};
        ListView lvEmployees = (ListView) view.findViewById (android.R.id.list);

        ListClientsCursorAdapter notes = new ListClientesCursorAdapter(context, R.layout.activity_fila_cliente, mCursorEmployee, from, to, 0);
        lvEmployees.setAdapter(notes);
                    //NOTE THAT I DONT HAVE TO SET A LISTENER FOR THIS ONE, AUTOMATICALLY
                    // THE onListItemClick IS CALLED

    }

Answer 1

您需要获取第二个 ListView 的引用，并且需要将 onItemClickListener 附加到它。

因为 ListFragment 将为 ID 为 @id/android:list 的 listView 附加 onItemClckListener

尝试在onCreateView获取参考

编辑：

  ListView list2=view.findViewById(R.id.listCompany);
   list2.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
    public void onItemClick(AdapterView<?> adapter, View view, int position, long arg)   {
            onListItemClick(adapter,view,position,arg);
    }
});

Answer 2

您需要将您的ListFragment 更改为Fragment，然后分别引用两个ListViews 并分配它们的侦听器：

ListView list = (ListView)findViewById(R.id.list);
ListView listCompany = (ListView)findViewById(R.id.listCompany);

list.setAdapter(...)
list2.listCompany(...)

每个ListFragment 一个ListView，或一个Fragment 中的多个ListViews，但一个ListFragment 中没有两个ListViews