您可以按照此代码为您的要求编写代码。
答案来自this tutorial,它涵盖了用户的行为:
首先你要创建两个drawables:
然后,根据这种方法,您必须在您的EditText 上实现addTextChangedListener 方法。之后,作为参数,您创建 TextWatcher 类的新实例并实现其方法:
etxtPin1.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
// TODO Auto-generated method stub
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s) {
if(etxtPin1.getText().toString().trim().length()==1){
etxtPin1.clearFocus();
etxtPin2.requestFocus();
etxtPin1.setBackgroundResource(R.drawable.pin_txt_bg_star);
}
}
});
然后,你必须实现setOnKeyListener及其方法onKey:
this.etxtPin1.setOnKeyListener(new View.OnKeyListener() {
public boolean onKey(View paramView, int paramInt, KeyEvent paramKeyEvent) {
if ((paramKeyEvent.getAction() == KeyEvent.ACTION_DOWN)&&(paramInt == 67) && (LoginActivity.this.etxtPin2.getText().length() == 0)) {
etxtPin1.requestFocus();
etxtPin1.setBackgroundResource(R.drawable.pin_txt_bg);
etxtPin1.setText("");
}
return false;
}
});
另一种方法:创建您自己的扩展PasswordTransformationMethod的类。
public class MyPasswordTransformationMethod extends PasswordTransformationMethod {
@Override
public CharSequence getTransformation(CharSequence source, View view) {
return new PasswordCharSequence(source);
}
private class PasswordCharSequence implements CharSequence {
private CharSequence mSource;
public PasswordCharSequence(CharSequence source) {
mSource = source; // Store char sequence
}
public char charAt(int index) {
return '*'; // This is the important part
}
public int length() {
return mSource.length(); // Return default
}
public CharSequence subSequence(int start, int end) {
return mSource.subSequence(start, end); // Return default
}
}
};
参考:In android how to show asterisk (*) in place of dots in EditText having inputtype as textPassword?
Reference