如何解析 JSON 字符串 Android答案

【问题标题】：How to Parse the JSON String Android如何解析 JSON 字符串 Android
【发布时间】：2013-06-05 10:59:54
【问题描述】：

我正在尝试解析下面的 JSONString

[[{"0":"
","title":" Technical Support Analyst in Noida","1":"
","Company Name":" Oracle","2":"
","Category":"Fresher","3":"
","Job Type":"Full Time","4":"
","Location":"Noida","5":"
","Job Qualification":"BE\/BTch\/Bsc\/Others","6":"
","Job Experience":"Freshers","7":"
","Job postdate":"2013-6-05","8":"
"}]]

这是我的代码：

// try parse the string to a JSON object
try {
    //jObj = new JSONObject(JsonString);
    JSONArray ja = new JSONArray(result);
    int size = ja.length();
    Log.d("tag", "No of Elements " + ja.length());
} catch (JSONException e) {
    Log.e("JSON Parser", "Error parsing data " + e.toString());
}

有人可以帮忙吗，我的代码不起作用？我想解析标题、公司名称、类别等...

【问题讨论】：

参考这个stackoverflow.com/questions/9605913/…
字符串不是有效的 json
stackoverflow.com/questions/8091051/… 和 stackoverflow.com/questions/3408985/…
我已将您的 json 字符串放入 jsonviewer.stack.hu 并显示有效的 json..

标签： java android json android-layout android-intent

【解决方案1】：

您需要从您的 jsonstring 创建JSONArray。

JSONArray 在 JSONArray 中，然后是 JSONObect..

 try {
        JSONArray ja = new JSONArray(buffer.toString());
        JSONArray innerJsonArray = ja.getJsonArray(0);
        JSONObject object = innerJsonArray.getJSONObject(0);
        String title = object.getString("title");                
     } 
     catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
     }

【讨论】：

【解决方案2】：

看看我写的使用本机工具和 Gson 库的 Json 解析指南：

Json Parsing

也许你会发现它很有用。您也可以从那里下载完整的项目并自己运行和测试。

【讨论】：

【解决方案3】：

您需要构建您的 json。

没有名为“结果”的数组。你要做的就是给 json 中的每一个元素命名一个唯一的名字，以便获取它。

如

  {"result":
    ["result1":["result2":{"0":"
    ","title":" Technical Support Analyst in Noida","1":"
    ","Company Name":" Oracle","2":"
    ","Category":"Fresher","3":"
    ","Job Type":"Full Time","4":"
    ","Location":"Noida","5":"
    ","Job Qualification":"BE\/BTch\/Bsc\/Others","6":"
    ","Job Experience":"Freshers","7":"
    ","Job postdate":"2013-6-05","8":"
    "}]]}

【讨论】：

【解决方案4】：

您可以尝试下面的代码来解析 JSON

{
"result": "success",
"countryCodeList":
[
{"countryCode":"00","countryName":"World Wide"},
{"countryCode":"kr","countryName":"Korea, Republic of"},
{"countryCode":"us","countryName":"United States"},
{"countryCode":"jp","countryName":"Japan"},
{"countryCode":"cn","countryName":"China"},
{"countryCode":"in","countryName":"India"}
]
}

解析代码

public static ArrayList<Country> ParseJson(String jsonstring) {

    ArrayList<Country> arrCountries = new ArrayList<Country>();

    String status;
    String message = "";
    try {


        JSONObject json = new JSONObject(jsonstring);

        status = json.getString("result");

        if (status.equalsIgnoreCase("success")) {


            JSONArray nameArray = json.names();
            JSONArray valArray = json.toJSONArray(nameArray);

            JSONArray valArray1 = valArray.getJSONArray(1);

            valArray1.toString().replace("[", "");
            valArray1.toString().replace("]", "");

            int len = valArray1.length();

            for (int i = 0; i < valArray1.length(); i++) {

                Country country = new Country();
                JSONObject arr = valArray1.getJSONObject(i);

                country.setCountryCode(arr.getString("countryCode"));
                country.setCountryName(arr.getString("countryName"));
                arrCountries.add(country);
            }
        }

    } catch (JSONException e) {
        Log.e("JSON", "There was an error parsing the JSON", e);
    }
    return arrCountries;
}

【讨论】：