如何按键过滤数组并使用javascript将值推送到另一个数组答案

【问题标题】：How to filter an array by key and push the value to another array using javascript如何按键过滤数组并使用javascript将值推送到另一个数组
【发布时间】：2020-11-25 20:06:03
【问题描述】：

这是我的第一个数组

data=  [{
  "id":1111,
  "date":"2020-08-03T08:00:00+00:00",
  "age":23,
   "email":"test@yahoo.com",
   "address":"phill road",
   "salary":1222.00
},

 {
  "id":222,
  "date":"2020-08-03T08:00:00+00:00",
  "age":24,
   "email":"tes22t@yahoo.com",
   "address":"phill2222 road",
   "salary":3344
}
]

第二个数组应该是这样的

  dataNew=  [1222.00,3344]

我需要第二个仅包含 工资值 的数组。如何过滤第一个数组，如果 keys name = "salary" ，将值推送到新数组。搜索了这么多建议，但似乎没有什么对我有用..

【问题讨论】：

标签： javascript arrays arraylist array-filter

【解决方案1】：

data=  [{
  "id":1111,
  "date":"2020-08-03T08:00:00+00:00",
  "age":23,
   "email":"test@yahoo.com",
   "address":"phill road",
   "salary":1222.00
},
 {
  "id":222,
  "date":"2020-08-03T08:00:00+00:00",
  "age":24,
   "email":"tes22t@yahoo.com",
   "address":"phill2222 road",
   "salary":3344
},
 {
  "id":223,
  "date":"2020-08-03T08:00:00+00:00",
  "age":24,
   "email":"tes22t@yahoo.com",
   "address":"phill2222 road"
}
]

console.log(data.filter(e => e.salary).map(e => e.salary));

【讨论】：

【解决方案2】：

data=  [{
  "id":1111,
  "date":"2020-08-03T08:00:00+00:00",
  "age":23,
   "email":"test@yahoo.com",
   "address":"phill road",
   "salary":1222.00
},

 {
  "id":222,
  "date":"2020-08-03T08:00:00+00:00",
  "age":24,
   "email":"tes22t@yahoo.com",
   "address":"phill2222 road",
   "salary":3344
}
]
const dataNew=[]
data.map(item=>item.salary?dataNew.push(item.salary):null)

【讨论】：

【解决方案3】：

这个

data = [{
    "id": 1111,
    "date": "2020-08-03T08:00:00+00:00",
    "age": 23,
    "email": "test@yahoo.com",
    "address": "phill road",
    "salary": 1222.00
  },

  {
    "id": 222,
    "date": "2020-08-03T08:00:00+00:00",
    "age": 24,
    "email": "tes22t@yahoo.com",
    "address": "phill2222 road",
    "salary": 3344
  }
]
arr = []
for (i = 0; i < data.length; i++) {
  console.log(data[i]['salary'])
  arr.push(data[i]['salary']);
}
console.log(arr)

【讨论】：

【解决方案4】：

你可以在数组上使用.map()

data.map(item => item.salary)

【讨论】：

【解决方案5】：

data=  [{
  "id":1111,
  "date":"2020-08-03T08:00:00+00:00",
  "age":23,
   "email":"test@yahoo.com",
   "address":"phill road",
   "salary":1222.00
},

 {
  "id":222,
  "date":"2020-08-03T08:00:00+00:00",
  "age":24,
   "email":"tes22t@yahoo.com",
   "address":"phill2222 road",
   "salary":3344
}]

data.map(item =>  item.salary)

【讨论】：