var result = Items.FindAll(x =>
properties.Any(p => p.PropertyType == typeof(string) &&
p.GetValue(x, null) == "Filip"));
显然,这是一个简单的、乐观的字符串比较(例如,您可能想使用string.Compare),但这应该使这个想法变得清晰。
编辑
dtb 对使用表达式树提出了很好的建议。您可以像这样以更快的方式完成您所追求的:
public static class PropertyScanner
{
static Func<TType, bool> CreatePredicate<TType, TValue>(TValue value, IEqualityComparer<TValue> comparer)
{
var arg = Expression.Parameter(typeof(TType), "arg");
Expression body = null;
Expression<Func<TValue, TValue, bool>> compare = (val1, val2) => comparer.Equals(val1, val2);
foreach (PropertyInfo property in typeof(TType).GetProperties(BindingFlags.Public))
{
if (property.PropertyType == typeof(TValue) || typeof(TValue).IsAssignableFrom(property.PropertyType))
{
Expression prop = Expression.Equal(Expression.Invoke(compare, new Expression[]
{
Expression.Constant(value),
Expression.Property(arg, property.Name)
}),
Expression.Constant(0));
if (body == null)
{
body = prop;
}
else
{
body = Expression.OrElse(body, prop);
}
}
}
return Expression.Lambda<Func<TType, bool>>(body, arg).Compile();
}
public static IEnumerable<TType> ScanProperties<TType, TValue>(this IEnumerable<TType> source, TValue value)
{
return ScanProperties<TType, TValue>(source, value, EqualityComparer<TValue>.Default);
}
public static IEnumerable<TType> ScanProperties<TType, TValue>(this IEnumerable<TType> source, TValue value, IEqualityComparer<TValue> comparer)
{
return source.Where(CreatePredicate<TType, TValue>(value, comparer));
}
}
这将允许您执行以下操作:
var result = Items.ScanProperties("Filip").ToList();