【问题标题】:How to convert function which ignores parameter in c++11?如何转换忽略c ++ 11中参数的函数?
【发布时间】:2014-10-03 06:18:14
【问题描述】:

我正在寻找一个更优雅的代码来忽略不必要的参数。有点反转 std::bind。

void doSomething(function<A(B)> callback); // Given function

// Instead of
void myDoSomething(function<A()> callback0) {
   doSomething([&](B b) { 
                  return callback0();
              });
}

// I want
void myDoSomething(function<A()> callback0) {
   doSomething(add_ignored_arg<B>(callback0));
}

【问题讨论】:

  • 您有一个带有参数的回调函数,并且您想要一种使用不带参数的回调函数来调用该函数的方法?
  • lambda 有什么问题?
  • T.C.,只有“重”语法

标签: c++ c++11 templates lambda c++14


【解决方案1】:

选项 #1

C++11基本解决方案,先注入一个被忽略的参数(DEMO 1):

template <typename Arg, typename R, typename... Args>
std::function<R(Arg, Args...)> add_ignored_arg(std::function<R(Args...)> f)
{
    return [f] (Arg&& /*arg*/, Args&&... args) { return f(std::forward<Args>(args)...); };
}

注意: std::forward&lt;Args&gt;(args) 可以正常工作(尽管Args&amp;&amp; 在这里不是转发引用),因为std::function 将按值传递的参数转换为右值引用,而左值引用根据规则折叠:&amp; &amp;&amp; -> &amp;

选项 #2

使用通用 lambda 的 C++14 基本解决方案,首先将忽略的参数注入 (DEMO 2):

template <typename Arg, typename R, typename... Args>
std::function<R(Arg, Args...)> add_ignored_arg(std::function<R(Args...)> f)
{
    return [f] (auto&& /*arg*/, auto&&... args) { return f(std::forward<decltype(args)>(args)...); };
}

选项#3

C++11 高级解决方案,将一个被忽略的参数注入到任何地方,并带有接受 原始函数指针std::function 包装器 (DEMO 3) 的附加重载:

template <std::size_t N, typename Arg, typename R, typename... Args, std::size_t... Before, std::size_t... After, typename Tuple = std::tuple<Args...>>
auto inject_param(index_sequence<Before...>, index_sequence<After...>)
    -> std::function<R(typename std::tuple_element<Before, Tuple>::type..., Arg, typename std::tuple_element<N + After, Tuple>::type...)>;

template <std::size_t N, typename Arg, typename R, typename... Args, std::size_t... Before, std::size_t... After, typename Tuple = std::tuple<Args...>>
auto add_ignored_arg(std::function<R(Args...)> f, index_sequence<Before...>, index_sequence<After...>)
    -> decltype(inject_param<N, Arg, R, Args...>(index_sequence<Before...>{}, index_sequence<After...>{}))
{
    return [f] (typename std::tuple_element<Before, Tuple>::type&&... before
                , Arg&& /*arg*/
                , typename std::tuple_element<N + After, Tuple>::type&&... after)
                {
                    return f(std::forward<typename std::tuple_element<Before, Tuple>::type>(before)...,
                             std::forward<typename std::tuple_element<N + After, Tuple>::type>(after)...);
                };
}

template <std::size_t N, typename Arg, typename R, typename... Args, typename Tuple = std::tuple<Args...>>
auto add_ignored_arg(std::function<R(Args...)> f)
    -> decltype(inject_param<N, Arg, R, Args...>(make_index_sequence<N>{}, make_index_sequence<sizeof...(Args) - N>{}))
{
    return add_ignored_arg<N, Arg>(f, make_index_sequence<N>{}, make_index_sequence<sizeof...(Args) - N>{});
}

template <std::size_t N, typename Arg, typename R, typename... Args, typename Tuple = std::tuple<Args...>>
auto add_ignored_arg(R(*f)(Args...))
    -> decltype(inject_param<N, Arg, R, Args...>(make_index_sequence<N>{}, make_index_sequence<sizeof...(Args) - N>{}))
{
    return add_ignored_arg<N, Arg>(std::function<R(Args...)>(f), make_index_sequence<N>{}, make_index_sequence<sizeof...(Args) - N>{});
}

注意:index_sequence 的实现在演示中。转发工作如选项 #1 中所述。

选项#4

使用泛型 lambda 和返回类型推导 (DEMO 4) 将忽略参数注入任何位置的 C++14 高级解决方案:

template <std::size_t N, typename Arg, typename R, typename... Args, std::size_t... Before, std::size_t... After, typename Tuple = std::tuple<Args...>>
auto add_ignored_arg(std::function<R(Args...)> f, std::index_sequence<Before...>, std::index_sequence<After...>)
    -> std::function<R(typename std::tuple_element<Before, Tuple>::type..., Arg, typename std::tuple_element<N + After, Tuple>::type...)>
{
    return [f] (auto&&... args)
                {
                    auto t = std::forward_as_tuple(std::forward<decltype(args)>(args)...);
                    return f(static_cast<typename std::tuple_element<Before, decltype(t)>::type>(std::get<Before>(t))...,
                             static_cast<typename std::tuple_element<N + After + 1, decltype(t)>::type>(std::get<N + After + 1>(t))...);
                };
}

template <std::size_t N, typename Arg, typename R, typename... Args, typename Tuple = std::tuple<Args...>>
auto add_ignored_arg(std::function<R(Args...)> f)
{
    return add_ignored_arg<N, Arg>(f, std::make_index_sequence<N>{}, std::make_index_sequence<sizeof...(Args) - N>{});
}

template <std::size_t N, typename Arg, typename R, typename... Args, typename Tuple = std::tuple<Args...>>
auto add_ignored_arg(R(*f)(Args...))
{
    return add_ignored_arg<N, Arg>(std::function<R(Args...)>(f), std::make_index_sequence<N>{}, std::make_index_sequence<sizeof...(Args) - N>{});
}

测试

struct B {};

void foo(int i, char c, double d)
{
    std::cout << i << " " << c << " " << d << std::endl;
}

void doSomething(std::function<void(int, char, B, double)> callback)
{
    callback(123, 'A', B{}, 3.14f);
}

void myDoSomething(std::function<void(int, char, double)> callback)
{
    doSomething(add_ignored_arg<2, B>(callback));
}

int main()
{
    myDoSomething(&foo);
}

输出:

123 A 3.14

Complete C++11 demo

Complete C++14 demo

【讨论】:

  • 通过引用捕获f 是个坏主意。
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