如何从android java中的Socket IO服务器返回的复杂对象中获取值答案

【问题标题】：How to get values from complex Object return from Socket IO server in android java如何从android java中的Socket IO服务器返回的复杂对象中获取值
【发布时间】：2016-03-18 06:59:32
【问题描述】：

在使用 android Socket.io nodejs 服务器时...

服务器返回用户数据列表

    private Emitter.Listener onSyncdData = new Emitter.Listener() {
        @Override
        public void call(final Object... args) {
            runOnUiThread(new Runnable() {
                @Override
                public void run() {                   
                    try {
                        Gson gson=new Gson();
                        String json = gson.toJson(args);

json 字符串包含

[{"values":
[{"nameValuePairs":{"Name":"Varun","EmailAddress":"","Latitude":"12","Langitude":"12","IsYours":"false","MobileNumber":"(903) 011-7411"}},
{"nameValuePairs":{"Name":"Varun","EmailAddress":"","Latitude":"12","Langitude":"12","IsYours":"false","MobileNumber":"(905) 970-8111"}},
{"nameValuePairs":{"Name":"Viany","EmailAddress":"","Latitude":"12","Langitude":"12","IsYours":"false","MobileNumber":"(900) 094-3111"}},
{"nameValuePairs":{"Name":"Pavan","EmailAddress":"","Latitude":"12","Langitude":"12","IsYours":"false","MobileNumber":"(779) 981-3111"}},
{"nameValuePairs":{"Name":"Rakesh","EmailAddress":"","Latitude":"12","Langitude":"12","IsYours":"false","MobileNumber":"(800) 895-3111"}},
{"nameValuePairs":{"Name":"","EmailAddress":"","Latitude":"12","Langitude":"12","IsYours":"true","MobileNumber":"15555215554"}}
]}]

我的问题是如何从 json 或 args 对象中检索 "Name","EmailAddress","MobileNumber"..etc。

【问题讨论】：

如果要读取一个JSON，调用GSON方法fromJson

标签： java android json node.js socket.io

【解决方案1】：

Gson 接受 JsonElement 但不接受 JSONObject(org.json)。因此，您需要在代码中执行以下操作，以免获得 nameValuePairs：

JSONObject obj = (JSONObject)args[0];//be sure to org.json but not com.google.gson 
PrasingClass parsingClass = gson.fromJson(obj.toString(),PrasingClass.class);

在没有 nameValuePairs 的情况下正确解析它。

【讨论】：