“任何？”类型的值没有成员“标签”

Question

我在我的自定义 tableViewCell 上添加了一个按钮，我希望在点击按钮后，它会根据按钮所在的单元格传递数据，因此要找出哪个单元格是按钮，我添加了一个标签，但是我收到了这个错误

 override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if segue.identifier == "goToLast" && sender is IndexPath {


             let dvc = segue.destination as! FinalClass 
            dvc.index = (sender as! IndexPath).row
            dvc.places = sortedArray
            dvc.userLocation = currentLocation

            }
        if segue.identifier == "goToReview" {

            let index3 = IndexPath(row: sender.tag, section: 0)
            let rev = segue.destination as! ReviewClass


        }

}

如何调整？

(cell.reviewButton.tag = indexPath.row) 这是我在 cellForRowAt 中添加的标签

更新

这是我的 VC 中的按钮操作

  @IBAction func ReviewButtonTap(_ sender: UIButton) {

      performSegue(withIdentifier: "goToReview" , sender: self)
    }

这是我的自定义 tableViewCell 类中的插座

 @IBOutlet weak var reviewButton: UIButton!

我不明白如何将此按钮与

else if segue.identifier == "goToReview", let button = sender as? UIButton, let rev = segue.destination as? ReviewClass {
            let index3 = IndexPath(row: button.tag, section: 0)

Answer 1

强制将可选的Any 向下转换为预期的UIButton 和IndexPath，并使用else 子句而不是if 两次

 if segue.identifier == "goToLast" {
        let dvc = segue.destination as! FinalClass 
        let indexPath = sender as! IndexPath
        dvc.index = indexPath.row
        dvc.places = sortedArray
        dvc.userLocation = currentLocation
}
else if segue.identifier == "goToReview" {
        let button = sender as! UIButton
        let index3 = IndexPath(row: button.tag, section: 0)
        let rev = segue.destination as! ReviewClass
}

或使用switch

 switch segue.identifier {
     case "goToLast":
        let dvc = segue.destination as! FinalClass 
        let indexPath = sender as! IndexPath
        dvc.index = indexPath.row
        dvc.places = sortedArray
        dvc.userLocation = currentLocation

    case "goToReview":
        let button = sender as! UIButton
        let index3 = IndexPath(row: button.tag, section: 0)
        let rev = segue.destination as! ReviewClass

    default: break
}

代码不得崩溃。如果是这样，你就犯了设计错误。

编辑

您必须将UIButton 实例（sender）从IBAction 传递到performSegue 的sender 参数。出口无关紧要。

performSegue(withIdentifier: "goToReview" , sender: sender)

Answer 2

如果它可以是不同的对象，您通常会在您的方法中提供一个发件人Any。在这种情况下，您需要将其类型转换为特定对象，最好在 swift 中使用let button = sender as? UIButton。

这样做您将收到一个可选值，其标记为button?.tag，其类型为Int?，然后再次禁止您创建索引路径。

所以这个方法的正确方法应该如下：

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "goToLast", let indexPath = sender as? IndexPath {
            let dvc = segue.destination as! FinalClass 
            dvc.index = indexPath.row
            dvc.places = sortedArray
            dvc.userLocation = currentLocation
    } else if segue.identifier == "goToReview", let button = sender as? UIButton {
            let index3 = IndexPath(row: button.tag, section: 0)
            let rev = segue.destination as! ReviewClass
    }
}

请注意，我已经更改了两个 if 语句，甚至设法删除了一个额外的强制展开（! 的东西）。如果您不介意强制解包会在不正确时使您的应用程序崩溃，那么您也可以这样做：

let index3 = IndexPath(row: (sender as! UIButton).tag, section: 0) 

但我建议您避免所有强制展开以提高稳定性。对于您的情况：

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "goToLast", let indexPath = sender as? IndexPath, let dvc = segue.destination as? FinalClass  {
            dvc.index = indexPath.row
            dvc.places = sortedArray
            dvc.userLocation = currentLocation
    } else if segue.identifier == "goToReview", let button = sender as? UIButton, let rev = segue.destination as? ReviewClass {
            let index3 = IndexPath(row: button.tag, section: 0)
    } else {
         print("ERROR: Incorrect configuration!") // Put a breakpoint here and analyze what was the identifier and what the sender so none of the statements were hit
    }
}

Answer 3

只是你需要用下面的方法改变你的segue方法

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "goToLast" && sender is IndexPath {


         let dvc = segue.destination as! FinalClass 
        dvc.index = (sender as! IndexPath).row
        dvc.places = sortedArray
        dvc.userLocation = currentLocation

        }
    if segue.identifier == "goToReview" {

        let index3 = IndexPath(row: (sender as! UIButton).tag, section: 0)
        let rev = segue.destination as! ReviewClass


    }
}

Answer 4

为了首先解决这个问题，你需要先在单元格中为你已经完成的行分配按钮标签。

cell.reviewButton.tag = indexPath.row

之后，您可以在行的单元格中的按钮上添加目标操作

cell.reviewButton.addTarget(self, action:#selector(self. 
func_Navigate(_:)), for:UIControlEvents.touchUpInside)

行的外侧单元格实现一个这样的功能：-

@IBAction func func_Navigate(_ sender: UIButton)
{

If sender.tag == 0

 {

    \\ here sender.tag = 0 means button belong from fist row of your table view. you can perform navigation like that :-
    self.performSegue(withIdentifier: "goToLast", sender: self)

}
else If sender.tag == 1

{
    \\ here sender.tag = 1 means button belong from second row of your table view. you can perform navigation like that :-
    self.performSegue(withIdentifier: "goToReview", sender: self)
}

Answer 5

您可以从发送者那里获取 UIButton 对象，然后 UIButton 对象有标签属性可以访问。

let button = sender as? UIButton
let index3 = IndexPath(row: button?.tag ?? 0, section: 0)