需要帮助...短信联系人匹配

Question

检查我的代码我一直在做一些关于短信应用程序的工作，现在我正在尝试将短信随附的地址与联系人中存储的号码进行匹配...

到目前为止，我无法匹配联系人并显示发件人的姓名，因为在模拟器上仅包含两个联系人...它匹配第一个并显示其姓名，而在电话上却找不到单个联系人...

public List<String> getSMS() {

        List<String> sms = new ArrayList<String>();
        Uri uriSMSURI = Uri.parse("content://sms/inbox");
        Cursor cur = getContentResolver().query(uriSMSURI, null, null, null,
                null);

        ContentResolver cr = getContentResolver();
        Cursor contactsCur = cr.query(ContactsContract.Contacts.CONTENT_URI,
                null, null, null, null);
        Cursor phoneCur = cr.query(
                ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                "DISPLAY_NAME = '" + name + "'", null, null);

        Log.v(LOG_TAG, "going in loop");
        if (contactsCur.getCount() > 0) {
            Log.v(LOG_TAG, "inside loop");
            while (contactsCur.moveToNext()) {
                Log.v(LOG_TAG, "cursor moving to next");
                id = contactsCur.getString(contactsCur
                        .getColumnIndex(ContactsContract.Contacts._ID));
                Log.i(LOG_TAG,"this is id: " + id);

                name = contactsCur
                        .getString(contactsCur
                                .getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
                Cursor phones = cr.query(Phone.CONTENT_URI, null,
                        Phone.CONTACT_ID + " = " + id, null, null);
                Log.i(LOG_TAG, "This is name "+name);
                while (phones.moveToNext()) 
                {
                     number = phones.getString(phones
                            .getColumnIndex(Phone.NUMBER));
                     String aNumber=number.replaceAll("-", "");
                     Log.i(LOG_TAG,"this is number :"+aNumber);

                    Log.v(LOG_TAG, "getting address and message");

                    while (cur.moveToNext()) {
                        String address = cur.getString(cur
                                .getColumnIndex("address"));
                        if(address.equals(aNumber))
                            address=name;
                        String body = cur.getString(cur
                                .getColumnIndexOrThrow("body"));

                        sms.add("Number: " + address+ " .Message: " + body);
                    }
                    Log.v(LOG_TAG, "closing phone cursor");
                    phoneCur.close();
                }

            }
        }

        return sms;

    }

Answer 1

查看此代码....

String phone_number = contacts
                        .getString(contacts
                                .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                Log.i(null, "Stage 12");
                // retrieve sms of phone_number from inbox
                Cursor sms = getContentResolver().query(
                        Uri.parse("content://sms/inbox"), null,
                        "address='" + phone_number + "'", null, null);
                Log.i(null, "Stage 13");


                if (sms.getCount() > 0) {
                    Log.i(null, "Stage 14");

                    sms.moveToFirst();
                    for (int j = 0; j < sms.getCount(); j++) {
                        Log.i(null, "Stage 15");

                        // get sms body
                        String text = sms.getString(sms.getColumnIndex("body"));
                        // add "phone_number" and "text" to a list
                        groupSms.add(phone_number + ":" + text);
                        Log.i(null, "Stage 16");

                        // move to next sms from phone_number
                        sms.moveToNext();
                    }
                }
                // move to next contact
                contacts.moveToNext();
            }
        }
        Log.i(null, "Stage 9");
        return groupSms;

下面提到的代码永远不会执行......它是上面代码的一部分......

if (sms.getCount() > 0) {
                        Log.i(null, "Stage 14");

                        sms.moveToFirst();
                        for (int j = 0; j < sms.getCount(); j++) {
                            Log.i(null, "Stage 15");

                            // get sms body
                            String text = sms.getString(sms.getColumnIndex("body"));
                            // add "phone_number" and "text" to a list
                            groupSms.add(phone_number + ":" + text);
                            Log.i(null, "Stage 16");

                            // move to next sms from phone_number
                            sms.moveToNext();
                        }

这让我很头疼...我无法弄清楚为什么这段代码永远不会执行...我正在我的 Galaxy 上运行代码...

任何帮助...？

Answer 2

我没有完全理解你在这里编码的内容。但是我得到了你的要求。所以我的建议是-尝试这种方式（因为现在没有时间，我没有尝试过，但从逻辑上它应该可以工作） ：

public List<String> getSMS() {

        List<String> sms = new ArrayList<String>();
        //fetch all inbox sms
        Cursor inboxCursor = getContentResolver().query(Uri.parse("content://sms/inbox"), null, null, null,null);

        if(inboxCursor.getCount()>0)
        {
            inboxCursor.moveToFirst();
            for(int i=0;i<inboxCursor.getCount();i++)
            {
                //get phone-number of sms
                String address=inboxCursor.getString(inboxCursor.getColumnIndex("address"));

                //fetch contacts with same phone-number
                Cursor contactCursor=getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.NUMBER+"='"+address+"'",null,null);

                if(contactCursor.getCount()>0)
                {
                    contactCursor.moveToFirst();

                    // fetch the name associated with that number in contacts saved
                    String name=contactCursor.getString(contactCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    //add number,name,message to list   
                    sms.add("Number: " + address+ " .Name: "+ name +".Message: " + body);
                }
                else 
                {  
                    // for unknown contact
                    // add number,name,message to list                     
                    sms.add("Number: " + address+ " .Name: Unknown .Message: " + body);
                }
                inboxCursor.moveToNext();
            }
        }
        return sms;
}

编辑：

将来自每个联系人的所有短信分组：

    List<String> groupSms=new List<String>(); 
    // retrieve all contacts
    Cursor contacts=getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                    null,null,null,null);     
    if(contacts.getCount()>0)
    {
        contacts.moveToFirst();
        for(int i=0;i<contacts.getCount();i++)
        {    
             // get phone number       
             String phone_number=contacts.getString(contacts.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)) ;
             // retrieve sms of phone_number from inbox
             Cursor sms=getContentResolver().query(Uri.parse("content://sms/inbox"), null, "address='"+phone_number+"'", null,null);
             if(sms.getCount()>0)
             {
                  sms.moveToFirst();
                  for(int j=0;j<sms.getCount();j++)
                  {
                      // get sms body
                      String text=sms.getString(sms.getColumnIndex("body"));    
                      // add "phone_number" and "text" to a list
                      groupSms.add(phone_number+":"+text);
                      // move to next sms from phone_number
                      sms.moveToNext();
                  }
             }
             //move to next contact
             contacts.moveToNext();
        }
    }

Answer 3

当您处理电话号码时，它 (https://code.google.com/p/libphonenumber/) 可能有助于概括它.... :)