在 Android 中对联系人进行排序

Question

    public void ReadContacts() {
    Cursor people = getContentResolver().query(Phone.CONTENT_URI, null, null, null,Phone.DISPLAY_NAME + " ASC ");
    int indexName = people
            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
    int indexNumber = people
            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);

    people.moveToFirst();
    do {
        name = people.getString(indexName);
        number = people.getString(indexNumber);

        contacts.put(name, number);

    } while (people.moveToNext());

    printHashMap(contacts);

}

public void printHashMap(HashMap<String, String> a) {

    for (Entry<String, String> lists : a.entrySet()) {
        Log.d(lists.getKey(), lists.getValue());
    }

}

尽管使用了 ASC，但联系人没有排序？你能帮我找出原因吗？ 我也使用了 upper() 方法

光标 cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, "upper("+ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + ") ASC");

Answer 1

您将（排序的）结果放在不保留元素顺序的 HashMap 中。使用 List 就可以了。

编辑：使用您在评论中建议的Tuple 类，它应该如下所示：

static class Tuple {
    public String name;
    public String number;

    public Tuple(String name, String number) {
        this.name = name;
        this.number = number;
    }
}

public void ReadContacts() {
    Cursor people = getContentResolver().query(Phone.CONTENT_URI, null,  null, null, Phone.DISPLAY_NAME + " ASC ");
    int indexName = people
            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
    int indexNumber = people
            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);

    List<Tuple> contacts = new ArrayList<Tuple>();

    people.moveToFirst();
    do {
        name = people.getString(indexName);
        number = people.getString(indexNumber);

        contacts.add(new Tuple(name, number));

    } while (people.moveToNext());

    printHashMap(contacts);

}

public void printList(List<Tuple> list) {

    for (Tuple tuple : list) {
        Log.d(tuple.name + ", " + tuple.number);
    }
}

但在这种情况下，我建议将 Tuple 类重命名为 Contact。拥有一个包含名为“name”和“number”的成员的元组类很奇怪。