【问题标题】:How can I pick a contact from call log?如何从通话记录中选择联系人?
【发布时间】:2012-01-25 21:09:33
【问题描述】:

如何从通话记录中挑选联系人?

这是我的代码,但是当我尝试 Intent.ACTION_PICK 时,它不起作用

Intent showCallLog = new Intent();
showCallLog.setAction(Intent.ACTION_VIEW);
showCallLog.setType(CallLog.Calls.CONTENT_TYPE);
context.startActivity(showCallLog); 

【问题讨论】:

标签: android android-intent android-contacts phone-call calllog


【解决方案1】:

我不确定是否可以使用 ACTION_PICK 完成,如果可行,您可以为此创建一个简单的选择对话框,例如:

public class MainActivity extends Activity {
        @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Button btnPick = (Button) findViewById(R.id.btnPick);
        btnPick.setOnClickListener(new OnClickListener() {
            public void onClick(View v) {
                String[] strFields = { android.provider.CallLog.Calls._ID,
                        android.provider.CallLog.Calls.NUMBER,
                        android.provider.CallLog.Calls.CACHED_NAME, };
                String strOrder = android.provider.CallLog.Calls.DATE + " DESC";
                final Cursor cursorCall = getContentResolver().query(
                        android.provider.CallLog.Calls.CONTENT_URI, strFields,
                        null, null, strOrder);

                AlertDialog.Builder builder = new AlertDialog.Builder(
                        MainActivity.this);
                builder.setTitle("Select recent contact");
                android.content.DialogInterface.OnClickListener listener = new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialogInterface,
                            int item) {
                        cursorCall.moveToPosition(item);
                        Toast.makeText(
                                MainActivity.this,
                                cursorCall.getString(cursorCall
                                        .getColumnIndex(android.provider.CallLog.Calls.NUMBER)),
                                Toast.LENGTH_LONG).show();
                        cursorCall.close();
                        return;
                    }
                };
                builder.setCursor(cursorCall, listener,
                        android.provider.CallLog.Calls.CACHED_NAME);
                builder.create().show();
            }
        });
    }
}

【讨论】:

    【解决方案2】:

    builder.setCursor(cursorCall, listener, android.provider.CallLog.Calls.CACHED_NAME);

    改为

     builder.setCursor(cursorCall, listener,
                        android.provider.CallLog.Calls.NUMBER);
    

    由于未显示未知数字..代码正在 100% 工作,谢谢

    【讨论】:

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