来自设备的电话号码返回 0

Question

我对 android 开发有点陌生，我现在完全被卡住了！ 所以我希望你能帮助我！

所以 - 我正在尝试从联系人选择器中获取联系人的电话号码和电子邮件地址。 但是当我显示输出时，它说它是0和null。 我究竟做错了什么？ 这是代码！

if (view == btnPhonebook2) {
        Intent intent = new Intent(Intent.ACTION_PICK, People.CONTENT_URI);
        startActivityForResult(intent, PICK_CONTACT);
    }

  public void onActivityResult(int reqCode, int resultCode, Intent data) {
    super.onActivityResult(reqCode, resultCode, data);
    switch (reqCode) {
    case (PICK_CONTACT):
        if (resultCode == Activity.RESULT_OK) {
            // String id = null;
            // FIRST TRY

              Uri contactData = data.getData(); Cursor c = managedQuery(contactData, null, null, null, null); 
              if(c.moveToFirst()) { 
                  String name = c.getString(c.getColumnIndexOrThrow(People.NAME)); 
                  int number = c.getInt(c.getColumnIndexOrThrow(People.PRIMARY_PHONE_ID));
                  String email = c.getString(c.getColumnIndexOrThrow(People.PRIMARY_EMAIL_ID));


              //+" : c.getInt(c.getColumnIndexOrThrow(People.NUMBER));
              Toast.makeText(getApplicationContext(),"you selected : "+name+"\n With the telephone number :"+number+"\n And the email :"+email,Toast.LENGTH_LONG).show();

              DialogInterface.OnClickListener dialogClickListener = new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface dialog, int which) {
                        switch (which){
                        case DialogInterface.BUTTON_POSITIVE:
                            Intent intent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "60158096"));
                              startActivity(intent);
                            break;

                        case DialogInterface.BUTTON_NEGATIVE:
                            Intent email = new Intent(Intent.ACTION_SEND);
                              email.putExtra(Intent.EXTRA_EMAIL, new String[]{"emailExample@gmail.com"});          
                              email.putExtra(Intent.EXTRA_SUBJECT, "subject");
                              email.putExtra(Intent.EXTRA_TEXT, "message");
                              email.setType("message/rfc822");
                              startActivity(Intent.createChooser(email, "Choose an Email client :"));
                            break;
                        }
                    }
                };

                AlertDialog.Builder builder = new AlertDialog.Builder(this);
                builder.setMessage("How will you contact: "+name).setPositiveButton("Call", dialogClickListener)
                    .setNegativeButton("Email", dialogClickListener).show();

当我显示字符串名称时 - 结果很好！？

Answer 1

我在here之前回答过类似的问题。

ContentResolver cr = getContentResolver(); 
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null); 
String phone = null;
if (cur.getCount() > 0) { 
  while (cur.moveToNext()) { 
    String id = cur.getString(cur .getColumnIndex(ContactsContract.Contacts._ID)); 
    if (Integer .parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) 
    { 
      Cursor pCur = cr.query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[] { id }, null); 
      while (pCur.moveToNext()) { 
        phone = pCur .getString(pCur .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
        // This was the phone number for that contact id...
      } 
    pCur.close(); 
    Cursor emailCur = cr.query( ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?", new String[] { id }, null);
    while (emailCur.moveToNext()) { 
    // For Email
      emailContact = emailCur .getString(emailCur .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA)); 
      emailType = emailCur .getString(emailCur .getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));
    } 
  } 
}

同样你可以得到image uri。
您的代码的问题在这里：

String name = c.getString(c.getColumnIndexOrThrow(People.NAME)); 
int number = c.getInt(c.getColumnIndexOrThrow(People.PRIMARY_PHONE_ID));
String email = c.getString(c.getColumnIndexOrThrow(People.PRIMARY_EMAIL_ID));

使用 String 类型而不是 int 和 Contacts.People class is deprecated from api 5。此外 People.PRIMARY_PHONE_ID 会给你 id 而不是 PhoneNumber。

String id = c.getString(c.getColumnIndex(People.PRIMARY_PHONE_ID));