【发布时间】:2017-02-05 12:49:23
【问题描述】:
我有一个警告对话框,如果手机上没有检测到互联网连接,它会向用户显示一条消息。如果有互联网连接,我如何检查并重试,如果仍然没有连接,对话框会再次出现?
public class Splash extends Activity {
private ProgressBar mProgress;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_PORTRAIT);
setContentView(R.layout.splash);
if (Internet()) {
splash();
} else {
showAlertDialog(Splash.this, "No Internet Access",
"No Internet Connection detected", false);
}
}
public void splash() {
mProgress = (ProgressBar) findViewById(R.id.progress);
mProgress.getProgressDrawable().setColorFilter(
Color.BLUE, android.graphics.PorterDuff.Mode.SRC_IN);
Thread timerTread = new Thread() {
public void run() {
try {
prog();
sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
Intent intent = new Intent(getApplicationContext(), Games.class);
intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
finish();
}
}
};
timerTread.start();
}
private void prog() {
for (int progress = 0; progress <= 100; progress += 20) {
try {
Thread.sleep(1000);
mProgress.setProgress(progress);
} catch (Exception e) {
e.printStackTrace();
}
}
}
public boolean Internet() {
ConnectivityManager connectivityManager = (ConnectivityManager) getBaseContext()
.getSystemService(Context.CONNECTIVITY_SERVICE);
if (connectivityManager != null) {
NetworkInfo[] info = connectivityManager.getAllNetworkInfo();
if (info != null)
for (int i = 0; i < info.length; i++)
if (info[i].getState() == NetworkInfo.State.CONNECTED) {
return true;
}
}
return false;
}
public void showAlertDialog(Context context, String title, String message, Boolean status) {
final AlertDialog alertDialog = new AlertDialog.Builder(context).create();
alertDialog.setTitle(title);
alertDialog.setMessage(message);
alertDialog.setButton(AlertDialog.BUTTON_POSITIVE, "Retry ", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
}
});
alertDialog.setButton(AlertDialog.BUTTON_NEGATIVE, "Exit ", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
finish();
System.exit(0);
}
});
alertDialog.show();
}
}
【问题讨论】:
-
为什么不使用广播接收器连续检查连接,而不是制作按钮?
标签: android android-alertdialog